Chebyshev’s Theorem establishes that at least 1 - 1/k² of the population lie among k standard deviations from the mean.
This means that for k = 2, 1 - 1/4 = 0.75. In other words, 75% of the total population would be the percentage of healthy adults with body temperatures that are within 2standard deviations of the mean.
The maximum value of that range would be simply μ + 2s, where μ is the mean and s the standard deviation. In the same way, the minimum value would be μ - 2s:
maximum = μ + 2s = 98.16˚F + 2*0.56˚F = 99.28˚F
minimum = μ - 2s = 98.16˚F - 2*0.56˚F = 97.04˚F
In summary, at least 75% of the amount of healthy adults have a body temperature within 2 standard deviations of 98.16˚F, that is to say, a body temperature between 97.04˚F and 99.28˚F.
Answer:
<u>Same side angles are supplementary</u>
L+k=180
18x-18+72=180
18x=126
x=7
m∠18(7)-18
= 108°
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have a grat day
Oder of operations is this;
Answer:
1 11/21
Step-by-step explanation:
6/7 + 2/3 = 32/21
32/21 simplified is 1 11/21
Answer:
Jon lost a total of 3 kilograms in these 3 months.
Step-by-step explanation:
Weight that Jon gained in December = 2.2 kilograms
Weight that Jon lost in January = 1.5 kilograms
Weight that Jon lost in February = 3.7 kilograms
Overall Change in his weight = Total Weight he gained - Total weight he Lost
Total weight he gained is 2.2 kilograms as he only gained weight in December. Total weight he lost will be sum of weights he lost in January and February.
So, total weight Jon lost = 1.5 + 3.7 = 5.2 kilograms
Thus,
Total change in Jon's Weight = 2.2 - 5.2 = -3.0 kilograms
This shows that Jon lost a total of 3 kilograms in these 3 months.
Conclusion:
The statement that best describe the total change in his weight is: Jon lost a total of 3 kilograms in these 3 months
