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alexandr402 [8]
3 years ago
8

Can someone please help me.There is not just one answer there can be multiple

Mathematics
2 answers:
poizon [28]3 years ago
7 0
I believe that c, d and f are right
Roman55 [17]3 years ago
3 0
Hi 3DST3!

The diameter of a circle is x 2 the radius. The radius is, as you checked, 5m. Therefore the answer cannot be A.

The circumference formulas are \pi * diameter or 2\pi (3.14 rounded)r. The radius of the circle is 5 and pi (rounded) = 3.14, therefore, 2*3.14*5. 2*3.14*5 = 31.4. Therefore b isn't a correct answer choice and neither is e. 

The diameter, as I said, is 2 * r. Our r is 5. 2 * 5 = 10. 10 is our diameter and C the correct answer choice. 

The area of a circle's formula is \pir^{2} Therefore 3.14 * 5^2 -> 3.14 * 25 = 78.5. D is correct. 

Answers that are correct:
C
D
F

Answers that are incorrect:
A
B
E
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Answer:

see the explanation

The solution's table in the attached figure

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

Let

y ----> the price

x ----> the weight

Find the value of the proportionality constant for each ordered pair in each table

k=\frac{y}{x}

If all the values of k are equal, then the table represents a proportional relationship between the variable x and the variable y

Table 1

For x=1.5 lb, y=$4.50 ---->  k=\frac{4.5}{1.50}=3

For x=2 lb, y=$9.00 ---->  k=\frac{9.00}{2}=4.5

The values of k are different

therefore

The table not represent a proportional relationship

Table 2

For x=10 g, y=$0.50 ---->  k=\frac{0.50}{10}=0.05

For x=15 g, y=$0.55 ---->  k=\frac{0.55}{15}=0.04

The values of k are different

therefore

The table not represent a proportional relationship

Table 3

For x=0.5 Kg, y=$0.75 ---->  k=\frac{0.75}{0.5}=1.5

For x=5 g, y=$7.50 ---->  k=\frac{7.50}{5}=1.5

The values of k are equal

therefore

<u><em>The table represent a proportional relationship</em></u>

Table 4

For x=1 oz, y=$2.00 ---->  k=\frac{2}{1}=2

For x=2 lb, y=$4.00

Convert lb to oz

Remember that

1 lb=16 oz

so

2 lb=2(16)=32 oz

For x=32 lb, y=$4.00 ---->  k=\frac{4}{32}=0.125

The values of k are different

therefore

The table not represent a proportional relationship

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therefore gradient of line A is 2 and line B is -1

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What is the main problem with this paragraph
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Answer:

A

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Sin∅=√3-1/2 find approximate value of sec∅(sec∅+tan∅)/1+tan²∅​
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Answer:

The approximate value of f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta} is 1.366.

Step-by-step explanation:

Let f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}, we proceed to simplify the formula until a form based exclusively in sines and cosines is found. From Trigonometry, we shall use the following identities:

\sec \theta = \frac{1}{\cos \theta} (1)

\tan\theta = \frac{\sin\theta}{\cos \theta} (2)

\cos^{2}+\sin^{2} = 1 (3)

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f(\theta) = \frac{\left(\frac{1}{\cos^{2}\theta}\right)\cdot (1+\sin \theta)}{\frac{1}{\cos^{2}\theta} }

f(\theta) = 1+\sin \theta

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