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2 years ago

376×74 help and show work

Mathematics

2 answers:

VikaD [51]2 years ago

5 0

here ya go! I hope this helps you! :)

hoa [83]2 years ago

3 0

Answer:

27,824

Step-by-step explanation:

i just calculated it.

You might be interested in

What number is added to make a perfect square ?

V125BC [204]

Answer:

2 is added

Step-by-step explanation:

5 0

2 years ago

Pls help me answer this question if correct I'll make brainylist!!!

Greeley [361]

Answer:

C. 11 3/4

Step-by-step explanation:

3 + 3 + 2 + 2 = 10

1/4 + 3/4 + 1/4 = 1 1/4

1/2 -> 2/4

2/4 + 1 1/4 = 1 3/4

10 + 1 3/4 = 11 3/4

6 0

2 years ago

Read 2 more answers

NEED HELP ASAP!! WILL MARK BRAINLIEST IF ITS RIGHT!!

Karo-lina-s [1.5K]

Answer:

First one: yes

Second one: yes

Third one: no

Step-by-step explanation:

To find the midpoint of a line segment, you take the x and y coordinates of the 2 points, add each of them up, and divide each of them by 2.

First one: x = (1+3)/2 = 2, y = (2+4)/2 = 3, so it's correct.

Second one: x = (-1+3)/2 = 1, y = (1+-1)/2 = 0, so it's correct.

Third one: x = (-3+-1)/2 = -2, y = (0+5)/2 ≠ 2, so it's not correct.

I really hope this helped.

3 0

2 years ago

Circletown's limits form a perfectly circular shape. It has a population of

Iteru [2.4K]

Answer:

3.64 Km.

Step-by-step explanation:

Given,

Total population = 20,000 people

Population density = 480 people per square kilometer

Area of the circle town

$A = \dfrac{20000}{480}$

$A = 41.667\ km^2$

Radius of the circle town

$\pi r^2 = 41.667$

$r = 3.64\ km$

Hence, the radius of circle town is equal to 3.64 Km.

5 0

3 years ago

Read 2 more answers

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago

376×74 help and show work​

376×74 help and show work