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Sonja [21]
3 years ago
6

A drawer contains 60 pairs of socks. Each pair is one of four colors. What is the minimum number of socks that must be drawn, at

random, from the drawer to ensure that a pair of matching-color socks is selected? Plz help!
Mathematics
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

Minimum 5 socks needs to be selected.

Step-by-step explanation:

Given that there are four different colors of socks.

So, if you pick 4 socks , in worst case it will be all four of different color.

now if you pick 5th socks it will be either of those four colors.

Hence, minimum 5 socks must be taken to ensure that  a pair of matching-color socks is selected.

______________________________________________

To elaborate it more,

let four colors be red, yellow, blue , green

if you pick 5 socks, then in worst case four will be all of different color

red, yellow, blue , green but fifth will be

  • If red socks, then there will 1 pair of red socks
  • If yellow socks, then there will 1 pair of yellow socks
  • If blue socks, then there will 1 pair of blue socks
  • If green socks, then there will 1 pair of green socks

Hence. minimum 5 socks needs to be selected.

_______________________________________

In general, if you have n objects of different colors then you need to take minimum n+1 number of object to have at least two object of same color.

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2 years ago
You roll a six-sided die twice. What is the probability of rolling a 3 and then a 5? A) 1 3 B) 1 6 C) 1 12 D) 1 36
Molodets [167]

Answer:

D) 1/36

Step-by-step explanation:

You are trying to roll a 3 the first time, and then a 5 the second time. This means that order matters.

It is given to you, that you are rolling a standard die (6-sides). The dice is ordered in the following: 1, 2, 3, 4, 5, 6

The first time, you are rolling for a 3. Note that there is only one 3 in the sequence, so your chance of rolling a 3 is 1 out of 6: 1/6.

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Next, multiply the two fractions together to find the probability of rolling a 3 and then a 5:

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4 0
3 years ago
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Find two integers whose sum is -20 and product is 99
Brums [2.3K]

Answer:

Step-by-step explanation:

let the integers be x and y

x+y=-20

y=-20-x

xy=99

x(-20-x)=99

-20x-x²=99

x²+20x+99=0

x²+11x+9x+99=0

x(x+11)+9(x+11)=0

(x+11)(x+9)=0

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Answer:

4.71 minutes

Step-by-step explanation:

Incomplete question [See comment for complete question]

Given

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First, calculate the volume of the cone.

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Make Time the subject

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Time= \frac{65.94in^3}{14in^3}min

Cancel out the units

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