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Mars2501 [29]
3 years ago
9

Find the ordered pair for the equation: y = 2x + 10 where x = 3

Mathematics
2 answers:
pogonyaev3 years ago
8 0
IT IS 15 BECAUSE YOU HAVE TO ADD IT UP

Arturiano [62]3 years ago
7 0
( 3, 16 ) 

Hope this helps you! 

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What’s the answer to this thank u for ur help:)
goldfiish [28.3K]

Answer:

b. DAC≅DBC

Step-by-step explanation:

∠DCB≅∠DCA=90° as they are right angles at the perpendicular lines

DC=DC reflexive property(they are the same line)

AC=CB they are both the radius of the same circle

DAC≅DBC   due to SAS(Side angle Side)

6 0
3 years ago
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Problem 5.A miner is trapped inside a mine and has access to 3 doors. The first door leads to a tunneland can take him to safety
Likurg_2 [28]

Answer:

Expected time is 15 hours for him to get to safety.

Step-by-step explanation:

We define X as the time that this miner would get to safety.

We define Y as the door he chooses initially.

P(Y= 1) = P(Y=2)=P(Y=3) = 1/3

We have E[X|Y=1] = 3

E[X|Y] = 5 hours + E[X}

E[X|Y] = 7 hours + E[X]

Then we have

E[X] = 1/3(3 + 5 + E[X] + 7 + E[X])

We cross multiply

3*E[X] = (15 + 2E[x])

3E[X] - 2E[X] = 15

E[X] = 15

So the time it would take to get him to safety is 15 hours

5 0
2 years ago
A student needed to prepare 500mL of 1X TAE buffer to run a QC gel. The stock solution in the lab is 5X TAE. What volumes of sto
Xelga [282]

Answer:

you need 100ml of 5X TAE and 400ml of water.

Step-by-step explanation:

You need to use a rule of three:

C_1V_1=C_2V_2

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\left \{ {{C_1= 5X} \atop {C_2=1X}} \right.

and

\left \{ {{V_1 = V_{TAE}} \atop {V_2=500ml}} \right.

Therefore:

V_{TAE} = \frac{V_2*C_2}{C_1}

V_{TAE} = 100ml

Then just rest the TAE volume to the final Volume and you get the amount of water that you need to reduce the concentration.

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2 years ago
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I think the answer would be
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2 years ago
Explain what the scale factor for each category means
Rina8888 [55]
The scale factor for math numbers are the numbers you multiply to get an anwser for its factor.
Ex: factor of 2 is 2,4,6,8 and so on with each number
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