Answer:
-5x+5
Step-by-step explanation:
i just got this question
Answer:
6x²y²
Step-by-step explanation:
6: 1 2 3 6
18: 1 2 3 6 9 18
36: 1 2 3 4 6 9 12 18 36
the common factor for 6 18 and 36 are
1 2 3 6
x² = x × x
y³ = y × y × y
x³ = x × x × x
y³ = y × y × y
x³ = x × x × x
y² = y × y
the common factor are for x and y are
x² y²
Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²
Answer:
<u> $50</u> is <u>27.02%</u> of <u>$185</u>.
Step-by-step explanation:
Money spent on clothing = $50
Money spent on Groceries = $100
Money spent on Gas = $35
Total money spent = $185
Our question is to find the percentage of total money that is spent on clothing.
Percentage money on clothing =
× 100
=
× 100
= 27.02% (approx)
Hence,<u> $50</u> is <u>27.02%</u> of <u>$185</u>.
Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°
<u>Step-by-step explanation:</u>
Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL
KM ≅ LM
3x + 23 = 7x - 37
23 = 4x - 37
60 = 4x
15 = x
KM = LM = 3x + 23
= 3(15) + 23
= 45 + 23
= 68
KL = 9x - 40
= 9(15) - 40
= 135 - 40
= 95
Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.
- Since N is the midpoint of KL and KL = 95, then NL = 47.5
- Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse
Use trig to solve for ∠L (which equals ∠K):
cos ∠L = 
cos ∠L = 
∠L = cos⁻¹ 
∠L = 45.7
Triangle sum Theorem:
∠K + ∠L + ∠M = 180°
45.7 + 45.7 + ∠M = 180
91.4 + ∠M = 180
∠M = 88.6
You have two triangles, ADC and ABC.
Sides AD and AB are congruent.
Sides DC and BC are congruent.
Side AC is congruent to itself.
By SSS, triangles ADC and ABC are congruent.
Corresponding parts of congruent triangles are congruent.
That means that angles DAC and BAC are congruent.
Angles DCA and BCA are congruent.
Since m<DAC = 32, then m<BAC = 32
Since m<DCA = 41, then m<BCA = 41.
Now you know the measures of two angles of triangle ABC.
The measures of the interior angles of a triangle add to 180.
You can find the measure of angle B.
m<BAC + m<B + m<BCA = 180
32 + m<B + 41 = 180
m<B + 73 = 180
m<B = 107