Look up the equation for it
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Answer:
Emma is right because Jon put ¨2.5¨ notebooks when there are really $5
Step-by-step explanation:
Answer:
i have made it in above picture hope it helps
Well, following the order of PEMDAS, I got choice B. 52
For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.
Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.
In this case, you square the number 5, which gives you F(5)=2(25)+2
After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.
Finally, you add them, which results in F=52.
By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.
Anyway, hope this helped! :-)
