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beks73 [17]
3 years ago
8

Solve the quadratic equation by completing the square x^2+5x-3=0

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0

{\tt{x =  \frac{ -b± \sqrt{ {b}^{2} - 4ac } }{2a} }}

{\tt{ x =  \frac{ - 5±\sqrt{{5}^{2}  - 4 \times 1 \times ( - 3)} }{2 \times 1} }}

{\tt{x =  \frac{ - 5±\sqrt{25 + 12} }{2} }}

{\tt{x =  \frac{ - 5 ±\sqrt{37}  }{2} }}

\:  \:

{\tt{x =  \frac{ - 5 +  \sqrt{37} }{2} }}

{\tt{x =  \frac{ - 5 -  \sqrt{37} }{2} }}

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Step-by-step explanation:

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3 years ago
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hoa [83]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
A. 4x^5+3x+2<br> B. 4x^2+3x+2x^5<br> C. 4x^5+3+2/x^5<br> D. 18x^5+12x+6
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3 years ago
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algol13

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Step-by-step explanation:

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6 0
3 years ago
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