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ryzh [129]
2 years ago
5

The total cost of a belt and a shirt was $78.10. If the price of the belt was $6.32 less than the shirt, what was the price of t

he belt? Express your answer as a simplified
fraction or a decimal rounded to two places
Mathematics
1 answer:
adoni [48]2 years ago
8 0
32 73/100 or 32.73
hope this helps
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Combine Like Terms: x^2 + y^2 + 3y^2 + 4x + 2x + 2 + 2
Serga [27]

Answer:

x^2 + 4y^2 + 6x + 4

Step-by-step explanation:

Arranging the terms;

x ^ 2 + y^2 + 3y^2 + 4x + 2x + 2 + 2

x^2 + 4y^2 + 4x + 2x + 2 + 2

x^2 + 4y^2 + 6x + 2 + 2

x^2 + 4y^2 + 6x + 4

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BRAINLIEST NO LINKS OR YOU WILL BE REPORTED!!!!!
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180

Step-by-step explanation:

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A carpenter is building a unique jewelry box in the shape of a right triangular prism. The base has measurements of 4 inches, 3
BlackZzzverrR [31]
Answer: The carpenter will need 84 square inches of wood.

In this problem we are looking for the surface area of the jewelry box. This box has 5 faces. The two triangles at each end and the 3 rectangle pieces between them.

The sides of the triangles are 3, 4, 5 which always forms a right triangle with legs of 3 and 4. Use the formula for the area of a triangle, we have 3 x 4 / 2 = 6. The area of each triangle is 6 square inches.

Now, the three sides, each one has a height of 6.
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5 x 6 = 30

If we add all the sides together, we get an area of 84 square inches.
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3 years ago
Part Sophia's brother, Stanley, is cooking carrots for the family dinner. He needs to make less than twice as many servings of c
Masteriza [31]

Answer:

Step-by-step explanation:

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If y is the number then y < 20

7 0
2 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
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