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3 years ago

PLEASE HELP ME WITH THISSSS!!!

Chemistry

1 answer:

Lilit [14]3 years ago

4 0

16) you can tell which craters are younger by them being small and you can tell which craters are older by them being larger.

17) The larger craters experienced energetic impacts because they are simply larger in size which makes them being impacted.

Hope this was helpful have a nice day :)

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A 30.0 g sample of a metal was heated in a hot water bath to 80°c. it was then quickly transferred to a coffee-cup calorimeter.

Annette [7]

when the metal is lost heat and the calorimeter of water is gained the heat

and when the heat lost = the heat gained so,

(M*C*ΔT)m = (M*C*ΔT)w

when Mm= mass of the metal = 30 g

Δ Tm = (80-25) = 55 °C

and Mw = mass of water = 100 g

Cw is the specific heat of water = 4.181 J/g.°C

ΔTw = (25-20) = 5 °C

so by substitution:

∴ 30* Cm*55 = 100 * 4.181 * 5

∴Cm (specific heat of metal) = (100*4.181*5)/(30*55)

∴C of metal = 1.267 J/g.°C

3 0

4 years ago

Read 2 more answers

Please help me

denis23 [38]

Answer:

it would be 335

Explanation:

3 0

3 years ago

The first-order decay of radon has a half-life of 3.823 days. How many grams of radon decomposes after 5.55 days if the sample i

Leni [432]

Answer:

The mass of radon that decompose = 63. 4 g

Explanation:

R.R = P.E/(2ᵇ/ⁿ)

Where R.R = radioactive remain, P.E = parent element, b = Time, n = half life.

Where P.E = 100 g , b = 5.55 days, n = 3.823 days.

∴ R.R = 100/ $2^{5.55/3.823}$

R.R = 100/ $2^{1.45}$

R.R = 100/2.73

R.R = 36.63 g.

The mass of radon that decompose = Initial mass of radon - Remaining mass of radon after radioactivity.

Mass of radon that decompose = 100 - 36.63

= 63.37 ≈ 63.4 g

The mass of radon that decompose = 63. 4 g

8 0

3 years ago

If 4.55 mol of calcium carbide (CaC2) reacts with an excess of water, how many moles of acetylene (C2H2), a gas used in welding,

Rina8888 [55]

Answer:

4.55 mol of C₂H₂

Explanation:

Let's verify the reaction:

CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂

Ratio is 1:1, so 1 mol of calcium carbide will produce 1 mol of acetylene.

4.55 mol of CaC₂ will make the same amount of C₂H₂

3 0

3 years ago

Read 2 more answers

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

Len [333]

Answer:

a. 1875 nm

b. 4051 nm

c. 1282 nm

These all are infrared electromagnetic radiation.

Explanation:

Our strategy here is to utilize the Rydberg equation for hydrogen atom electronic transition.

1/λ = Rh x (1/n₁² - 1/n₂²) where λ is the wavelength

Rh is Rydberg constant

n₁ and n ₂ are the energy levels ( n₁ < n₂ )

Now lets star the calculations.

a. n₁ = 3, n₂ = 4

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/4²) = 5.333 x 10⁵/m

λ = 1/(5.333 x 10⁵ /m) = 1.875 x 10⁻⁶ m

Converting λ to nanometers:

1.875 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1875 nm

b. n₁ = 4, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/4² - 1/5²) = 2.468 x 10⁵/m

λ = 1/(2.468 x 10⁵/m) = 4.051 x 10⁻⁶ m

4.051 x 10⁻⁶ m x (1 x10⁹ nm/m) = 4051 nm

c. n₁ = 3, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/5²) = 7801 x 10⁵/m

λ = 1/(7801 x 10⁵/m) = 1282 x 10⁻⁶ m

1282 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1282 nm

All of these transitions fall in the infrared region of the spectrum.

8 0

3 years ago