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Sphinxa [80]
2 years ago
6

Write down in terms of n, an expression for the nth term

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
7 0

Answer:

a_{n} = - 7n - 1

Step-by-step explanation:

There is a common difference between consecutive terms , that is

- 15 - (- 8) = - 22 - (- 15) = - 29 - (- 22) = - 36 - (- 29) = - 7

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 8 and d = - 7 , then

a_{n} = - 8 - 7(n - 1) = - 8 - 7n + 7 = - 7n - 1

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8 0
3 years ago
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Help ! please :D<br> i only have about 15 min &gt;
guapka [62]

Answer:

  1. First option
  2. Third option
  3. Last option

I hope this helps!

6 0
3 years ago
Y^2 isolate 19x^2+4y^2=25
qaws [65]

Answer:

Simplifying

x2 + -4y2 = 25

Solving

x2 + -4y2 = 25

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y2' to each side of the equation.

x2 + -4y2 + 4y2 = 25 + 4y2

Combine like terms: -4y2 + 4y2 = 0

x2 + 0 = 25 + 4y2

x2 = 25 + 4y2

Simplifying

x2 = 25 + 4y2

Reorder the terms:

-25 + x2 + -4y2 = 25 + 4y2 + -25 + -4y2

Reorder the terms:

-25 + x2 + -4y2 = 25 + -25 + 4y2 + -4y2

Combine like terms: 25 + -25 = 0

-25 + x2 + -4y2 = 0 + 4y2 + -4y2

-25 + x2 + -4y2 = 4y2 + -4y2

Combine like terms: 4y2 + -4y2 = 0

-25 + x2 + -4y2 = 0

The solution to this equation could not be determined.

Step-by-step         sorry if im wrong

6 0
3 years ago
5x - 5 = 5(x+1) need help
bezimeni [28]

Answer:

There are no solutions.

Step-by-step explanation:

5x-5=5(x+1)

5x-5=5x+5

    +5     +5

5x=5x+10    

-5x -5x

0x=10

There are no possible answers.

Hopefully this helps.

7 0
3 years ago
The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
lyudmila [28]

Answer:

  • <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>

Explanation:

<u>Rewrite the table and the choices for better understanding:</u>

<em>Enrollment at a Technical School </em>

Year (x)       First Year f(x)      Second Year s(x)

2009                  785                        756

2010                   740                        785

2011                    690                        710

2012                   732                         732

2013                   781                          755

Which of the following statements is true based on the data in the table?

  • The solution to f(x) = s(x) is x = 2012.
  • The solution to f(x) = s(x) is x = 732.
  • The solution to f(x) = s(x) is x = 2011.
  • The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>

Thus, the correct choice is the third one:

  • The solution to f(x) = s(x) is x = 2012.
5 0
3 years ago
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