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nikklg [1K]
3 years ago
9

Carlos purchased an antique chair for $56.

Mathematics
1 answer:
timama [110]3 years ago
4 0

Answer:

about  22 percent

Step-by-step explanation:

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A city garden club is planting a square garden. They drive pegs into the ground at each corner and tie strings between each pair
Dafna1 [17]

Answer:

first blank is "rhombus"

second blank is "rectangle"

third blank is "are congruent"

Step-by-step explanation:

5 0
3 years ago
Find the coordinates of the intersection of the diagonals of the parallelogram with the vertices W(−2, 5), X(2, 5), Y(4, 0),
emmasim [6.3K]

Using the midpoint formula, the coordinates of the intersection of the diagonals of the parallelogram is: (1, 2.5).

<h3>What are Diagonals of a Parallelogram?</h3>

The diagonals of a parallelogram bisect each other, therefore, the coordinates of their intersection can be determined using the midpoint formula, which is: M(\frac{x_2 + x_1}{2}, \frac{y_2 + y_1}{2}).

A diagonal is XZ.

X(2, 5) = (x1, y1)

Z(0, 0) = (x2, y2)

Plug in the values

M(\frac{0 + 2}{2}, \frac{0 + 5}{2})

= (1, 2.5).

Learn more about the diagonals of a parallelogram on:

brainly.com/question/12167853

#SPJ1

7 0
1 year ago
A 2x2 square is centered on the origin. It is dilated by a factor of 3. What are the coordinated of the vertices of the square?
Alexxx [7]

<u>Answer</u>:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

The ratio of area of  larger square to smaller square is 9:1

<u>Step-by-step explanation:</u>

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1),  B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

To find the area of the small square

the side  of the small square is 2 units

so the are of the small square is 2^2 = 4 square units

To find the area of the larger square

lets find the side AB of the square using distance formula

=>\sqrt{(x_2 -x_1)^2 +(y_2-y_1)^2}

=>\sqrt{(3 - (-3))^2 +(-3 - (-3))^2}

=>\sqrt{(3 +3)^2 +(-3 +3)^2}

=>\sqrt{(6)^2 +(0)^2}

=>\sqrt{36}

=>6

AB =6 units

In a square all the sides will be equal

Now the area of the larger square will be

6^2

36 square units

The ratio of larger square to smaller square is

=>36 : 4

=>9 : 1

5 0
3 years ago
Find the ordered pairs for the x- and y-intercepts of the equation 3x − 2y = 18 and select the appropriate option below.
horsena [70]
Pretty sure the answer is B
8 0
3 years ago
The length of a rectangular is 5/2 unites greater then twice its width if it’s width w which expression gives the perimeter of t
strojnjashka [21]

If width is w the length can be represented as 5/2+2w.

Formula for perimeter is 2l + 2w

So it would be 2w + 2(5/2 + 2w)

OR 2w + 5 + 4w

OR 6w + 5



See if this helps ;)

5 0
3 years ago
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