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m_a_m_a [10]
3 years ago
8

What is the slope of the line that passes through the points (-3,-2) and (2,-4)?

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0
The slope of the line that passes through the points is y=8/5x
nikitadnepr [17]3 years ago
6 0

Answer:

slope = gradient...

gradient (m) = <u>∆</u><u>y</u>

∆x

= <u>-</u><u>4</u><u> </u><u>-</u><u> </u><u>-</u><u>2</u>

2 - -3

= <u>-</u><u>4</u><u> </u><u>+</u><u> </u><u>2</u>

2 + 3

= <u>-</u><u>2</u>

5

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<h3>Answer:   c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\

With a = -5 and b = 4, we have

f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\

So,

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Use algebra to solve for c

-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\

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Step-by-step explanation:

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Step-by-step explanation:

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Alenkasestr [34]

Answer:

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Step-by-step explanation:

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