The Importance of Color Theory in Painting. Color Theory was a required foundations course in the Visual Communication Design program at BYU, so all the design students took it–the interior designers, graphic designers, industrial designers, and the illustrators.
D. 0.0001.......first the zero before the decimal point is devided by 2....so it gives out 0 as a reminder so u right 0. at first then to do the part after decimal...first multiply 0.625 by 2 which gives out 0.125 as a fractional number so 0 would be the number after "0." ...and again the answer 0.125 is multiplied by 2 which gives out 0.25....so again we get a zero as an integer so now it would be "0.00..." ....again multiply 0.25 by 2 which gives out 0.5....again the integer is 0....so we add another 0 after 0.00....which would then become 0.000.....after that again multiply 0.5 by 2 which would give 1 as a result....as the fractional part is over, u need to stop here....so add that 1 after the 0.000 which gives 0.0001 as a final result.
Answer:
CUBIE MiniDrawer Bin
Explanation:
MiniDrawers comes in two configurations, and each fitting comes in one drawerslot. The MiniDrawer (1-6) comes with the most primary pocket dimensions. And we have the 18-tray MiniDrawer (1-8) comes with another dimensions in its basic form. You will in fact find various pocket dimensions like 1,2,3,4,6,12, and these comes within the 18-tray and 6-tray MiniDrawers. And they come in all the dispensing modes mentioned in the question. Hence, the above answer. The answer is clear from the options as well, and since it has the matrix mode as well apart from single dose mode and multi dose mode.
Answer:
Computer is an example of electronic device.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
