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3 years ago

How can we control the quality in the tourism industry?

Business

1 answer:

laila [671]3 years ago

5 0

Answer:

Avoid mainstream and/or iconic destinations. ...

Make “second city” tourism a habit. ...

Highlight lesser known places. ...

Travel as slowly as possible. ...

Travel in smaller groups. ...

Make sure people in your photos have given consent.

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Question 11 of 20

Inessa [10]

Answer: Gus should keep the files A. and D.

Explanation:

I don’t believe that he should keep B. due to D. showing an update to B. so, he shouldn’t keep B. so that he doesn’t get confused by both B. and D. being in the files.

8 0

1 year ago

What is the difference between the value of a firm's final product and the value added by the firm to the final product?

sweet [91]

Answer:

The value of a firm's final product is the selling price whereas value added refers to the addition of value to the raw material (intermediate products).

Explanation:

The term "value added" describes the enhancement a company gives to its product before offering it to the customer. It can be considered as an extra special feature added by a company to increase the value of a final product.

3 0

3 years ago

The unemployment rate in a town in which 65,400 persons are employed and 11,000 are unemployed equals:

Over [174]

Based on the number of people that are employed and those who are unemployed in this town, the unemployment rate is 14.4%.

<h3>What is the unemployment rate?</h3>

The unemployment rate can be found by the formula:
= Employed people / (Unemployed + Employed people)

Solving gives:

= (11,000) / (65,400 + 11,000)

= 11,000 / 76,400

= 14.4%

In conclusion, the rate is 14.4%.

Find out more on the unemployment rate at brainly.com/question/13280244.

7 0

2 years ago

The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana

storchak [24]

Answer:

a) $P(492$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 0.949)= P(Z$

b) $P(505$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 1.898)= P(Z$

c) $P(484$

And we can use excel or the normal standard table to find this probability:

$P(-1 < Z< 1)= P(Z$

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

$X \sim N(502,100)$

Where $\mu=502$ and $\sigma=100$

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)$

And for this case we want this probability:

$P(502-10 < \bar X < 502+10)$

And for this case we can use the z score given by:

$z= \frac{\bar X -\mu}{\sigma_{\bar x}}$

And if we use this formula we got:

$P(492$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 0.949)= P(Z$

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

$X \sim N(515,100)$

Where $\mu=515$ and $\sigma=100$

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)$

And for this case we want this probability:

$P(515-10 < \bar X < 515+10)$

And for this case we can use the z score given by:

$z= \frac{\bar X -\mu}{\sigma_{\bar x}}$

And if we use this formula we got:

$P(505$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 1.898)= P(Z$

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

$X \sim N(494,100)$

Where $\mu=494$ and $\sigma=100$

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)$

And for this case we want this probability:

$P(494-10 < \bar X < 494+10)$

And for this case we can use the z score given by:

$z= \frac{\bar X -\mu}{\sigma_{\bar x}}$

And if we use this formula we got:

$P(484$

And we can use excel or the normal standard table to find this probability:

$P(-1 < Z< 1)= P(Z$

3 0

3 years ago

"Fresh Veggies, Inc. (FVI), purchases land and a warehouse for $460,000. In addition to the purchase price, FVI makes the follow

Artyom0805 [142]

Answer:

Cost of land = $519,000

Explanation:

<em>According to International Accounting Standards (IAS) 16, property plants and equipments, the cost of land includes all of the cost necessary to bring and make it ready for the intended use. </em>

<em>These costs include purchase cost, fees and commission associated with the purchase transaction. </em>

<em>Further more, included in the historical cost are the net demolition cost of old structure to prepare the land for use. Net cost here means cost of demolition less any incidental proceed from the old structure.</em>

Note that all the costs incurred by FVI as reported all fall into the above definition of cost of land.

Therefore the cost of the land would be

=460,000 + 26,000 + 1,600+ 5,400 + 26,000

= $519,000

5 0

3 years ago