Answer:
4200
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Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
276
Step-by-step explanation:
240+(240*.15) = 276
Answer: -56 -17 0 5 34
Step-by-step explanation:
The more left you go on a number line the smaller it is
Answer:
if you meant 9x+10y=4 then the x intercepts are (4/9,0) and the y intercepts are (0,2/5).
Step-by-step explanation: