Answer:![\dfrac{1}{60} ms^{-1}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B60%7D%20ms%5E%7B-1%7D)
Explanation:
Speed of an object is defined as the ratio of the distance covered by the object to the time taken to cover that distance.
Let
be the speed of the object.
Let
be the distance travelled by the object.
Let
be the time taken by the object.
So,![s=\frac{D}{t}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7BD%7D%7Bt%7D)
s=![\frac{2}{120}=\frac{1}{60}ms^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B120%7D%3D%5Cfrac%7B1%7D%7B60%7Dms%5E%7B-1%7D)
So,the speed of the car is ![\frac{1}{60}ms^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B60%7Dms%5E%7B-1%7D)
Answer:
Hey, bro here is the explanation....
Explanation:
Hope it helps...
Rearranging formulas is all about simple algebra rules. Just like when solving for x in an equation, you're just isolating whichever variable you want. I'll work this one out for you and hopefully it'll help, but if you need more explanation, then feel free to comment!
D = ViT + 0.5at² Subtract ViT from both sides
D - ViT = 0.5at² Divide both sides by 0.5t²
I wrote this step out a little more to show how your fraction will cancel
= a I like to flip these around so the single variable is on the right
a = ![\frac{D - ViT}{0.5t^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BD%20-%20ViT%7D%7B0.5t%5E%7B2%7D%20%7D%20)
A) experimental because he isn’t sure and is testing out