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Advocard [28]
4 years ago
5

Which of the follow are examples of an object accelerating? (choose 4) A car turning a corner A ball rolling on the ground and s

lowing down OA box being pushed on the ground at a constant velocity A ball falling A paper falling to the ground with a constant speed OA ball moving up in the sky but slowing down A chair sitting on the ground
Physics
1 answer:
notsponge [240]4 years ago
5 0

Answer:

Cart spinning, ball rolling, ball falling, ball going up

Explanation:

The acceleration of a body is a vector magnitude, this means that it also has a module, direction, therefore, any of the two things that change, the acceleration changes. Let's examine the examples:

- Car turning a corner. In this case the speed direction is changing, which is reflected in an acceleration of the system

- A ball rolling on the ground. As the speed is decreasing the acceleration module is changing

- Ball falling in this case the speed increases, so there is an acceleration

- Constant speed box. Here with the constant speed in module and direction There is no acceleration

- Paper falling with constant speed. As the speed is constant There is no acceleration

- Ball moving up. In this case the module gives the speed is decreasing, There is an acceleration

- Chair on the floor zero speed and does not change, therefore there is no acceleration

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A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
GREYUIT [131]

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

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Answer:

b

Explanation:

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Answer:

Explanation:

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.3) True. The frequency creates a forced oscillation, whereby the atoms re-emit at the same incident frequency

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