Answer:
Described below
Explanation:
1) Solids: In solids, the strong attractive forces between the particles ensure that the particles are packed tightly enough and this means little or no movement between each other. However, when they experience vibration which has relationship with the kinetic energy between them
2) Liquids; In liquids due to the lesser forces of attraction between the particles, it means they tend to glide over each another but however, toward the bottom of the container they will settle. This means that the attractive forces between the liquid particles are barely strong enough to hold onto a specific volume. However, they are not strong enough to keep the molecules from sliding over one other.
3) Gases; In gases, there is almost no existing attractive force in most cases and as a result we can say the kinetic energy of the gas molecules is always greater than the attractive force between them and they are therefore far apart from each other and also move independent of each other.
Speed = distance/time
= 400/72
=5.55 m/s
The frequency is how many per second:
(6 swings)/(30 sec) = (6/30) swing/sec = 0.2 per sec = 0.2 Hz .
The period is how long each one takes, or seconds per swing.
It's exactly the flip of frequency.
So we could just take the frequency, flip it, and find 1 / 0.2 ,
but let's do it the long way:
(30 sec) / (6 swings) = (30/6) sec/swing = 5 seconds .
When Emmett is lifting a box
vertically, the forces that must be added to calculate the total force are: the
gravitational force, tension force(the force exerted by Emmett to the box and
the force exerted by the box to Emmett), and air resistance force.
Here given that x is inversely depends of y
so as we increase the value of y so due to inverse dependency it will decrease the value of x
So here we can also say that when x inversely depends on y
so the product of x and y will remain constant here
so here the graph should be like this that if we increase the quantity on x axis then it will decrease the other quantity on y axis
<u><em>So here best appropriate graph must be option A</em></u>
