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Answer:
8 classes
Step-by-step explanation:
Given
Required
The number of class
To calculate the number of class, the following must be true
Where k is the number of classes
So, we have:
Take logarithm of both sides
Apply law of logarithm
Divide both sides by log(2)
Round up to get the least number of classes
When looking for extremes on an interval, one must examine the turning points and the values of the function at the ends of the interval. Here the turning points are where the derivative is zero:. j
... 12x² -12x -24 = 0
... 12(x -2)(x +1) = 0
Since the turning points, x=-1, x=2, are in the interval we have four function values to compute.
... f(-2) = ((4(-2) -6)(-2) -24)(-2) +1 = -7
... f(-1) = ((4(-1) -6)(-1) -24)(-1) +1 = 15
... f(2) = ((4(2) -6)(2) -24)(2) +1 = -39
... f(3) = ((4(3) -6)(3) -24)(3) +1 = -17
This shows the extremes to be at the turning points.
The absolute minimum value is -39 at x=2.
The absolute maximum value is 15 at x=-1.
