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2 years ago

PLEASE HELP ME!! ILL GIVE BRAINLIEST!!

Mathematics

2 answers:

Natalka [10]2 years ago

6 0

Answer:

Step-by-step explanation:

1/4 is .25

4 fourths is 1. 4 times 7 equals 28 hamburgers. one half is two fourths. 28+2=30 hamburgers.

Olegator [25]2 years ago

5 0

No of hamburgers she can make

$\\ \sf\longmapsto 7\dfrac{1}{2}\div \dfrac{1}{4}$

$\\ \sf\longmapsto \dfrac{15}{2}\times \dfrac{4}{1}$

$\\ \sf\longmapsto \dfrac{60}{2}$

$\\ \sf\longmapsto 30$

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A class of 24 students went on a picnic. They had a choice between having a turkey sandwich or a vegetarian sandwich. Eighteen s

Alekssandra [29.7K]

I believe it is the ratio 3 : 1.

18 students chose the turkey sandwich.

Since the class has a total of 24 students, we can deduce that 6 students chose the vegetarian sandwich.

This gives us a ratio of 18 : 6.

When simplified, we get a ratio of 3 : 1.

5 0

3 years ago

50 PTS! NEED HELP NOW!

nordsb [41]

Answer:

maybe its just me but I cant see it :( blurry

Step-by-step explanation:

4 0

3 years ago

Evaluate ㏒ b 1, b > 0.

IrinaVladis [17]

Answer:

The solution is 1.

Step-by-step explanation:

Logarithm:

Suppose we have a logarithmic equation in the following format:

$\log_{a} b = c$

It means that:

$a_c = b$

In this question:

$\log_{b} 1 = x$

Which means that:

$b^x = 1$

Every number, elevated to 0, is 1. So

$b^0 = 1$

Which means that the solution is $x = 1$

7 0

3 years ago

PLEASEEEEE HELPPPPP Quick 15 points

zheka24 [161]

Answer:

Neither

Step-by-step explanation:

Since we only know the measure of the angles, we can only say the triangles are similar, not congruent. We need at least one side measurement on each triangle to determine if the triangles are congruent. And it would have to be the same side measurement. Then we could use ASA (Angle side Angle) or AAS ( Angle Angle side) to determine congruence.

The triangles are similar

62+39 +79 = 180

The three angles are the same

<A = 62 = <X = 62

<B = 39 = <Y = 39

<C = 79 = <Z = 79

This is shown by AAA similarity

5 0

3 years ago

A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H

andrey2020 [161]

Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}$

solve for "x"

what's "y"? well, y = 100 - x

4 0

3 years ago