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3 years ago

An angle whose measure is degree134° is bisected. What is the measure of each of the two new angles?

Mathematics

1 answer:

Olenka [21]3 years ago

4 0

Answer:

Each angle is 67 degrees

Step-by-step explanation:

Bisected angles are divided in half

134/2 =67

Each angle is 67 degrees

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What is this expression in simplified form 5/2 times 9/6? A.90 B.90/3 C.45/2 D. 45/3

alekssr [168]

5√2 · 9√6

Simplify.

5 × 9 √ 2 x 6 ⇒ Multiply 2 × 6.

5 × 9 √12

Simplify √12 to 2√3.

5 × 9 × 2√3 ⇔ Multiply

90√3

Therefore, the <u>correct alternative</u> is <u>option "B".</u>

8 0

2 years ago

If you vertically stretch the exponential function f(x)=2^x by a factor of 3, what is the equation of the new function

AleksAgata [21]

Answer:

$y=3*2^{x}$

Step-by-step explanation:

A vertical stretch of a function means the output values have changed by a factor of 3 or multiplication by 3. Recall, an exponential function has the basic form

$y=ab^{2}$ .

If our equation is $f(x)=2^x$ , then a=1. To stretch it vertically by a factor of 3, we multiply a by 3. So 1(3)=3. The value of a now becomes 3.

$y=3*2^{x}$

7 0

3 years ago

Find the value of c that makes t^2 - 22t+ c a perfect square trinomial.

allochka39001 [22]

The expression is a perfect square trinomial if and only if c = 121.

<h3>How to get the value of c?</h3>

A perfect square trinomial is written as:

(a + b)^2 = a^2 + b^2 + 2ab

In this case, we have:

t^2 - 22t + c

We can rewrite this as:

t^2 - 2*11*t + c

Then we have:

a = t

b = -11

And we will have that:

c = b^2 = (-11)^2 = 121

Then we have:

t^2 - 2*11*t + 121

Which is a perfect square trinomial:

(t - 11)^2 = t^2 - 22t + 121

Learn more about perfect squares:

brainly.com/question/1538726

#SPJ1

8 0

1 year ago

What is the distance between points A and B?

Galina-37 [17]

Answer:

6 units

Step-by-step explanation:

We require to calculate the absolute value so as to consider the measure both ways, that is

AB = | 1 - (- 5) | = | 1 + 5 | = 6

BA = | - 5 - 1 | = | - 6 | = 6

6 0

3 years ago

Find the exact value of tan(165°) using a difference of two angles

Katyanochek1 [597]

Answer: $-2+\sqrt{3}$

=========================================================

Work Shown:

Apply the following trig identity

$\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\$

Now let's rationalize the denominator

$\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\$

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

$\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949$

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as $\sqrt{3}-2$ but it's the same as above.

5 0

3 years ago