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2 years ago

4. In slope-intercept form, what is the equation of a line perpendicular toy - 2x + 7 that passes

Mathematics

1 answer:

Phoenix [80]2 years ago

7 0

Answer:

y = (-1/2)x + 21/2

Step-by-step explanation:

Given equation:

y - 2x + 7

Coordinates = (5,8)

Find:

Perpendicular equation

Computation:

y = mx + c

y - 2x + 7

y = 2x - 7

So,

m = 2

The negative reciprocal of 2 is -1/2

So,

For,

Coordinates = (5,8)

y = mx + c

8 = (-1/2)(5) + c

8 = -5/2 + c

c = 8 + 5/2

c = 21 /2

So,

y = mx + c

y = (-1/2)x + 21/2

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What is the equation of the line that is parallel to the line y =1/3 x + 4 and passes through the point (6, 5)?

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Read 2 more answers

X-1/x-2+x+3/x-4=2/(x-2).(4-x)

Varvara68 [4.7K]

The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

According to the statement

we have given that the equation and we have to prove that the given answer is a correct answer for those equivalent equation.

So, The given expression are:

$\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}$

And we have to prove the answer.

So, For this

$\frac{x-1}{x-2} +\frac{x+3}{x-4}$

$\frac{({x-1}) ({x-4}) +({x+3})({x-2})} {(x-2) (x-4)}$

Then the equation become

$\frac{x^{2} -4x -x +4 + x^{2} -2x + 3x -6 }{(x-2) (x-4)}$

Now solve it then

$2x^{2} - 4x -2 / (x-2) (x-4)$

Now take 2 common from answer then equation become

$\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}$

Hence proved.

So, The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

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10 months ago