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umka2103 [35]
3 years ago
7

How would you solve this, need help

Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0

Answer:1,829

Step-by-step explanation:

spayn [35]3 years ago
6 0

ok umm i fell asleep bye

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Which graph can be used to find the solution(s) to 4x = –4x
Ira Lisetskai [31]
I got this graph for 4x = -4x

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3 years ago
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Is this correct? The answer I picked was the only one that had no limit. If I did it correctly the other choices limit was zero.
andriy [413]

Step-by-step explanation:

These are all examples of p-series:

∑(1 / nᵖ), where p>0.

If p > 1, the series converges.  If 0 < p ≤ 1, the series diverges.

First option:

∑(1/n⁵)

Here, p = 5.  Since 5 > 1, the series converges.

Second option:

∑((√n+3)/n³)

∑((√n)/n³) + ∑(3/n³)

∑(1/n^2.5) + 3 ∑(1/n³)

In the first sum, p = 2.5.  In the second sum, p = 3.  Both are greater than 1, so the series converges.

Third option:

∑((n−4)/(n⁴√n))

∑(1/(n³√n)) − ∑(4/(n⁴√n))

∑(1/n^3.5) − 4 ∑(1/n^4.5)

In the first sum, p = 3.5.  In the second sum, p = 4.5.  Both are greater than 1, so the series converges.

Fourth option:

∑(1/∛n)

∑(1/n^⅓)

Here, p = ⅓.  This is less than 1, so the series diverges.

Note: if a series is converging, then the limit is 0.

However, if the limit of a series is 0, it does not necessarily mean that series is converging.

Here, the limit of all 4 options is 0.  However, the fourth option is a diverging series.

6 0
4 years ago
Use the fundamental identities to simplify the expression.<br> 9tantheta9cottheta/9sectheta
Mnenie [13.5K]
[9tan(θ) * 9cot(θ)] / 9sec(θ)

First cancel out the 9's:

tan(θ)cot(θ)/sec(θ)

Recall the following trig identities:

tan = sin/cos

cot = cos/sin

sec = 1/cos

Thus, we can rewrite the expression as:

[ (Sin(θ)/cos(θ)) *(cos(θ)/sin(θ)) ] / (1/cos(θ))

In the numerator, the sine's and cosine's cancel each other out:

1 / (1/cos(θ))

which we can rewrite as cos(θ).
8 0
4 years ago
Round 462093 to the nearest 10 000
Georgia [21]
462,093 round to the nearest ten thousand is 60,000 because 2 is less and 6 is greater so 6 stay the same
7 0
4 years ago
Jacob invested $300 in a savings account and earned $81 in simple interest at the end of 9 years. what was the interest rate
Brilliant_brown [7]

Answer:

A.

Step-by-step explanation:

We use the simple interest equation of A=P(1+rt).

A-the total amount with interest earned

P-the initial amount or principal

r-rate

t-time in years

We substitute the values P=300, A=381, and t=9. We then solve for r.

381=300(1+9r)

We divide both sides by 300.

\frac{381}{300}=\frac{300(1+9r)}{300}

Simplify.

1.27=1+9r

We subtract 1 from both sides.

1.27-1=1-1+9r

Simplify.

0.27=9r

We divide by 9.

\frac{0.27}{9}=\frac{9r}{9}

r=0.03

We need to convert the decimal to a percentage by multiplying by 100.

The interest rate is 3%.


7 0
4 years ago
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