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Gekata [30.6K]
2 years ago
13

4<-2x+3<9 Graph the inequality

Mathematics
1 answer:
Maksim231197 [3]2 years ago
8 0

look at the screenshot :)

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PLEASE HELP ASAP In this task, you will practice finding the area under a nonlinear function by using rectangles. You will use g
mrs_skeptik [129]

Answer:

a) 1280 u^{2}

b) 1320 u^{2}

c) \frac{4000}{3} u^{2}

Step-by-step explanation:

In order to solve this problem we must start by sketching the graph of the function. This will help us visualize the problem better. (See attached picture)

You can sketch the graph of the function by plotting as many points as you can from x=0 to x=20 or by finding the vertex form of the quadratic equation by completing the square. You can also do so by using a graphing device, you decide which method suits better for you.

A)

So we are interested in finding the area under the curve, so we divide it into 5 rectangles taking a right hand approximation. This is, the right upper corner of each rectangle will touch the graph. (see attached picture).

In order to figure the width of each rectangle we can use the following formula:

\Delta x=\frac{b-a}{n}

in this case a=0, b=20 and n=5 so we get:

\Delta x=\frac{20-0}{5}=\frac{20}{5}=4

so each rectangle must have a width of 4 units.

We can now calculate the hight of each rectangle. So we figure the y-value of each corner of the rectangles. We get the following heights:

h1=64

h2=96

h3=96

h4= 64

h5=0

so now we can use the following formula to find the area under the graph. Basically what the formula does is add the areas of the rectangles:

A=\sum^{n}_{i=1} f(x_{i}) \Delta x

which can be rewritten as:

A=\Delta x \sum^{n}_{i=1} f(x_{i})

So we go ahead and solve it:

A=(4)(64+96+96+64+0)

so:

A= 1280 u^{2}

B) The same procedure is used to solve part B, just that this time we divide the area in 10 rectangles.

In order to figure the width of each rectangle we can use the following formula:

\Delta x=\frac{b-a}{n}

in this case a=0, b=20 and n=10 so we get:

\Delta x=\frac{20-0}{10}=\frac{20}{10}=2

so each rectangle must have a width of 2 units.

We can now calculate the hight of each rectangle. So we figure the y-value of each corner of the rectangles. We get the following heights:

h1=36

h2=64

h3=84

h4= 96

h5=100

h6=96

h7=84

h8=64

h9=36

h10=0

so now we can use the following formula to find the area under the graph. Basically what the formula does is add the areas of the rectangles:

A=\sum^{n}_{i=1} f(x_{i}) \Delta x

which can be rewritten as:

A=\Delta x \sum^{n}_{i=1} f(x_{i})

So we go ahead and solve it:

A=(2)(36+64+84+96+100+96+84+64+36+0)

so:

A= 1320 u^{2}

c)

In order to find part c, we calculate the area by using limits, the limit will look like this:

\lim_{n \to \infty} \sum^{n}_{i=1} f(x^{*}_{i}) \Delta x

so we start by finding the change of x so we get:

\Delta x =\frac{b-a}{n}

\Delta x =\frac{20-0}{n}

\Delta x =\frac{20}{n}

next we find x^{*}_{i}

x^{*}_{i}=a+\Delta x i

so:

x^{*}_{i}=0+\frac{20}{n} i=\frac{20}{n} i

and we find f(x^{*}_{i})

f(x^{*}_{i})=f(\frac{20}{n} i)=-(\frac{20}{n} i)^{2}+20(\frac{20}{n} i)

cand we do some algebra to simplify it.

f(x^{*}_{i})=-\frac{400}{n^{2}}i^{2}+\frac{400}{n}i

we do some factorization:

f(x^{*}_{i})=-\frac{400}{n}(\frac{i^{2}}{n}-i)

and plug it into our formula:

\lim_{n \to \infty} \sum^{n}_{i=1}-\frac{400}{n}(\frac{i^{2}}{n}-i) (\frac{20}{n})

And simplify:

\lim_{n \to \infty} \sum^{n}_{i=1}-\frac{8000}{n^{2}}(\frac{i^{2}}{n}-i)

\lim_{n \to \infty} -\frac{8000}{n^{2}} \sum^{n}_{i=1}(\frac{i^{2}}{n}-i)

And now we use summation formulas:

\lim_{n \to \infty} -\frac{8000}{n^{2}} (\frac{n(n+1)(2n+1)}{6n}-\frac{n(n+1)}{2})

\lim_{n \to \infty} -\frac{8000}{n^{2}} (\frac{2n^{2}+3n+1}{6}-\frac{n^{2}}{2}-\frac{n}{2})

and simplify:

\lim_{n \to \infty} -\frac{8000}{n^{2}} (-\frac{n^{2}}{6}+\frac{1}{6})

\lim_{n \to \infty} \frac{4000}{3}+\frac{4000}{3n^{2}}

and solve the limit

\frac{4000}{3}u^{2}

4 0
3 years ago
Tom viaja 60 millas por hora yendo a una ciudad vecina y 50 millas por hora regresando usando la misma carretera. condujo un tot
victus00 [196]

Answer:

do you mind translating it

3 0
2 years ago
Use the coordinate grid to determine the coordinates of point A;
faltersainse [42]

Answer:

Step-by-step explanation:

The coordinates of point P are (-1.4,0.6)

Step-by-step explanation:

We are given A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole unit of the grid.

that means each grid has a value of 0.2.

" A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis "

As P lies on the left of the y-axis and above the x-axis hence the x-value will be negative and y-value will be positive.

According to the given information P lies 7 grid lines to the left of y-axis.

i.e. it has x-value -7×0.2= -1.4

and 3 grid lines above the x-axis i.e. it has y-value:

y-value= 3×0.2=0.6

Hence, the coordinates of Point P are (-1.4,0.6).

Click to let others know, how helpful is it

PLEASE MARK AS THE BRAINIEST

8 0
3 years ago
Read 2 more answers
3x + 1 − 4x3 + 6x6 −2x2 standard form
Molodets [167]
<span>6x6 - 4x3 - 2x2 + 3x + 1</span>
7 0
3 years ago
What happens to the value of the expression \dfrac5x+5 x 5 ​ +5start fraction, 5, divided by, x, end fraction, plus, 5 as xxx de
aleksandr82 [10.1K]

Answer:

It increases

Step-by-step explanation:

(5/x) + 5

As x decreases, 5/x increases.  So the expression increases.

5 0
3 years ago
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