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3 years ago

10

According to newton’s second law, if there is a net force, there will be

2 answers:

yaroslaw [1]3 years ago

4 0

Mark the other person brainliest plz

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

The object will have an acceleration and the object's velocity will change.

Explanation:

If there is a net force acting on an object, the object will have an acceleration and the object's velocity will change. Newton's second law states that for a particular force, the acceleration of an object is proportional to the net force and inversely proportional to the mass of the object.

<u><em>PLS MARK BRAINLIEST</em></u>

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What is the centripetal acceleration of a small Laboratory Centrifuge in which the tip of the test tube is moving at 19.0 meters

Shalnov [3]

Answer:

3610 m/s^2

Explanation:

The centripetal acceleration of the tip of the test tube is given by:

$a=\frac{v^2}{r}$

where

v = 19.0 m/s is the velocity of the tip

r = 10.0 cm = 0.1 m is the radius of the circular trajectory of the tip

Substituting the numbers into the formula, we find

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4 years ago

Two coils that are separated by a distance equal to their radius and that carry equal currents such that their axial fields add

jok3333 [9.3K]

Answer:

When x = 2.8 cm, $B_{x1} = 0.0265 T$

When x = 5.5 cm, $B_{x2} = 0.0209 T$

when x = 7.3 cm, $B_{x3} = 0.0169 T$

When x = 11.0 cm, $B_{x4} = 0.0103 T$

Explanation:

According to Biot-Savart law,

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When x₂ = 5.5cm = 0.055 m

$B_{x2} = \frac{300 *(4\pi * 10^{-7} ) * 17 *0.11^{2} }{2(0.055^{2} +0.11^{2} )^{3/2} }\\B_{x2} = 0.0209 T$

When x₃ = 7.3 cm = 0.073 m

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When X₄ = 11.0 cm = 0.11 m

$B_{x4} = \frac{300 *(4\pi * 10^{-7} ) * 17 *0.11^{2} }{2(0.11^{2} +0.11^{2} )^{3/2} }\\B_{x4} = 0.0103 T$

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4 years ago

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Lyrx [107]

Answer:

Heat is removed from it.

Explanation:

A object will become cold when it loses its heat to its surroundings. I would look up the 3 Principles of Heat Transfer.

I hope this helped! :)

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allochka39001 [22]

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3 years ago

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Leya [2.2K]

Answer:

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Explanation:

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Substitute the given parameters into the formula for velocity

Velocity = 30m/60s

Velocity = 1/2 m/s

Average Velocity = 0.5m/s

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3 years ago