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kow [346]
3 years ago
6

Which object will NOT allow an electric current to flow through it?

Physics
1 answer:
galben [10]3 years ago
6 0

Answer: C. A rubber eraser

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4 kg
nirvana33 [79]

Answer:

E = 62.72 J

Explanation:

Given that,

The mass of a ball, m = 4 kg

The teacher raised the lawn bowling ball to a height of 1.6 meters before they released it.

We need to find the gravitational potential energy of the ball.

We know that,

E = mgh

Where

g is acceleration due to gravity

So,

E = 4 kg × 9.8 m/s² × 1.6 m

E = 62.72 J

So, the gravitational potential energy of the ball is equal to 62.72 J.

3 0
2 years ago
Calculate the gravitational potential energy a 1kg ball has when thrown 3 m into the air. The gravitational field strength on ea
Andrei [34K]

Answer:

P.E.=29.4Nm

Explanation:

given data

m=1kg

h=3m

g=9.8m/s²

to find

gravitational potential energy=P.E.=?

solution

P.E.=mgh

PUTTING VALUES

P.E.=1kg×9.8m/s²×3m

P.E.=29.4Nm

3 0
3 years ago
Is it First or Second law Newtons law? Fill in the blanks
solniwko [45]

Answer:

1. Second Law

2. First Law

3. First Law

4. Second Law

3. First law

7 0
2 years ago
Read 2 more answers
A car is moving at 18 m/s when it accelerates at 8 m/s2 for 2 sec. What is his new velocity ?
ra1l [238]
Vf= at + Vi
Since at = 8m/s2 * 2 = 16m/s2
Vi=18m/s
=>Vf = 16m/s2 + 18m/s = 34m/s
So, the new velocity is 34m/s
5 0
3 years ago
An electron has a constant acceleration of +3.3 m/s2. at a certain instant its velocity is +8.6 m/s. what is its velocity (a) 2.
Citrus2011 [14]
Hello!


The velocity function is:

\mathsf{V = V_0 + at}\\ \\ \mathsf{V = 8.6 +3.3t}


a) 2.3 s earlier, we can make t = -2.3 s, in relation to our initial time:

\mathsf{V = 8.6 + 3.3\cdot(-2.3)}\\ \\ \mathsf{V = 8.8-7.59}\\ \\ \boxed{\mathsf{V = 1.21 \ m/s}}

b) Now we can make t = 2.3 s:

\mathsf{V = 8.6 + 3.3\cdot2.3}\\ \\ \mathsf{V = 8.6 + 7.59}\\ \\ \boxed{\mathsf{V = 15.59 \ m/s}}
7 0
3 years ago
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