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vovikov84 [41]
3 years ago
7

Which of these tables represent a linear function?

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

B because the rates are steady

Step-by-step explanation:

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PLEASE HELP I GIVE THANKS
MaRussiya [10]

first one is <u>=,</u><u /> second is <u>C,</u><u /> third is <u>B</u>
7 0
3 years ago
If R is the midpoint of QS, RS= 2x - 4, ST = 4x-1, and RT = 8x - 43, find QS.
Pepsi [2]

Answer: QS=68 units

Step-by-step explanation:

<em>RT=RS+ST</em>

<em>8x-43=2x-4+4x-1</em>

<em>8x-43=6x-5</em>

<em>8x-43-6x=6x-5-6x</em>

<em>2x-43=-5</em>

<em>2x-43+43=-5+43</em>

<em>2x=38</em>

<em>Divide both parts of the equation by 2:</em>

<em>x=19</em>

<em>QS=RS+RQ</em>

<em>As, RS=RQ</em>

<em>QS=2RS</em>

<em>QS=(2)((2)(19)-4))</em>

<em>QS=(2)(38-4)</em>

<em>QS=(2)(34)</em>

<em>QS=68</em>

6 0
1 year ago
A customer at Marty’s Fruit Stand picks a sample of 3 oranges at random from a crate containing 60 oranges, of which 4 are rotte
pychu [463]

Answer:

340 ways

Step-by-step explanation:

Given:

Total number of oranges = 60

Number of rotten oranges = 4

Number of oranges picked = 3

Now, number of good oranges = Total number - Rotten oranges

                                                    = 60 - 4 = 56

Now, we need to pick at least two rotten oranges.

So, the possible outcomes can be as follows:

  1. 2 rotten oranges + 1 good orange = 3 oranges
  2. 3 rotten oranges + 0 good orange = 3 oranges

Now, number of ways of picking 'r' distinct objects from a total of 'n' objects is given  as:

^nCr=\frac{n!}{r!(n-r)!}

Now, picking 2 rotten oranges from a total of 4 rotten oranges is:

^4C_2=\frac{4!}{2!2!}=\frac{4\times 3\times 2}{4}=6

Similarly, picking 3 rotten oranges from a total of 4 rotten oranges is:

^4C_3 =\frac{4!}{3!\times1!}=\frac{4\times 3!}{3!}=4

Now, picking 1 good orange from a total of 56 good oranges is:

^{56}C_1=56

Picking 0 good oranges means picking no good oranges.

Therefore, the total number of ways of picking at least 2 rotten oranges is the sum of the above two possibilities and is given as:

At least 2 rotten out of 3 picked = (2 rotten and 1 good) or 3 rotten

                                                       = 6 × 56 + 4

                                                       = 336 + 4 = 340 ways

Therefore, there are 340 ways of picking at least 2 rotten oranges when 3 oranges are picked from a total of 60 oranges.

8 0
4 years ago
I need help with this ... I don't understand it ..can anyone please help me with it .. It is due today... Please help me with th
Pavlova-9 [17]

Answer:

Plug in the x value that's given to find f(x)

So if you do it for the first one where x is -2 then f(x) should equal -23.

Do that for all of them and graph the coordinates and you should be fine

5 0
3 years ago
Read 2 more answers
Which transformation is happening in the image below​
Natali5045456 [20]

Answer:Translation

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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