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igomit [66]
2 years ago
9

One of the angles in an intersecting line mesures 30

Mathematics
1 answer:
asambeis [7]2 years ago
7 0

Think of the point, P,  where the lines intersect as the center of a circle.  The four angles with vertex P add up to 360 degrees.  The given angle and its paired vertical angle are both 30 degrees.  So, the other two angles are also vertical angles with sum 300 degrees (so each of them is a 150 degree angle).  

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Are the following fractions proportional?? .4/.8 and .71/.4
Neporo4naja [7]

Answer:

yes they are

Step-by-step explanation:

see nobody answers correctly:)

4 0
3 years ago
You spend 3 2/5 hours hiking and an additional 1/2 hour to rest.
Ket [755]

Answer:

Step-by-step explanation:

3 2/5 minus 1/2 after finding common denominator.

Answer:

29/10

Then simplify

4 0
3 years ago
3/5 of Jill's 30-page photo album is full. She wants to set aside 1/4 of the pages that are left for photos of her vacation. How
Mumz [18]
3/5 of the album is full....leaving 2/5 pages that are not full. 2/5(30) = 60/5 = 12 pgs not full (12 remaining pages)
she wants to set aside 1/4 of the remaining pages...
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3 0
3 years ago
Read 2 more answers
Can anyone help me evaluate this f(x)=8+4x the functions are 0 and -2.
Fynjy0 [20]

Answer: f(0)=8

f(-2)=0

Step-by-step explanation:

f(0)=8+4(0)

f(0)=8+0

f(0)=8

f(-2)=8+4(-2)

f(-2)=8+(-8)

f(-2)=8-8

f(-2)=0

3 0
1 year ago
If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.
Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

<em></em>

Step-by-step explanation:

Given

f(x)=x^3-12x^2+35x-24

f(8) = 0

Required

Find all zeros of the f(x)

If f(8) = 0 then:

x = 8

And x - 8 is a factor

Divide f(x) by x - 8

\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}

Expand the numerator

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}

Rewrite as:

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}

Factorize

\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}

Expand

\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}

Factorize

\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}

\frac{f(x)}{x - 8} = (x - 1)(x - 3)

Multiply both sides by x - 8

f(x) = (x - 1)(x - 3)(x - 8)

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

7 0
3 years ago
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