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Nata [24]
3 years ago
5

Round 768 to the nearest 10

Mathematics
2 answers:
uysha [10]3 years ago
7 0

Answer: 770

Step-by-step explanation: To round 768 to the nearest 10, we first find the digit in the rounding place which in this case is the 6 in the tens place.

Next, we look at the digit to the right of the 6 which is 8. According to the rules of rounding, since the digit to the right of the rounding place is greater than or equal to 5, we round up.

So in this problem, since 8 is greater than or equal to 5, we round down. This means that the digit in the rounding place which is 6 moves up to 7 and we add a 0 to all the digits that are right of 7.

Therefore, 768 rounded to the nearest 10 is 770.

algol133 years ago
6 0
770 because the 1 is higher than 5 so you round up
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Answer:

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Step-by-step explanation:

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PLEASE HELP ME IM STRUGGLING!!!
Kitty [74]

Answer:

The required answer is c=7\sqrt{3}

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\

Substituting the values we get

\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7

Now in Triangle ADC Tangent identity we have

\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}

Substituting the values we get

\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}

The required answer is c=7\sqrt{3}

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