Make an argument for why (4^2)^4=(4^4)^2

1 answer:

6 0

I hate when it comes to explaining but I gave it my best!

(4^2)^4 is the same as (4^4)^2 because they’re both being squared and multiplied by the a number equaling to the same number, but written differently.

4^2=16 , whereas 4^4=256
HOWEVER
16^4=65536 and 246^2=65536.

Therefore both equal to the same number. It depends on the exponents, and multiplication. If it were to be a different exponent, then they wouldn’t have been the same

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2 plez!!!?!?!?!?!?!?!?!??!!??!?!?!!??!?!?! I can’t figure it out I’ve tried everything it’s due tomorrow AHAHAHAH

harkovskaia [24]

So to do this one, you have to do the problem backwards!

The equation looks like this with everything plugged in:

272.2 = 2(3.14)r

You are looking for r, so start dividing

272.2 = 2(3.14)r
136.1 = (3.14)r
43.3 = r

Therefore the radius is about 43.3 in.

I hope I helped!

5 0

2 years ago

Will give brainiest answer, I need step-by-step answer

Korvikt [17]

Answer: Choice A

The volume expression is 4/3 times pi times (3x)^3

===================================================

The volume of a sphere is found through the formula

V = (4/3)*pi*r^3

so we start with the fraction 4/3, multiply it with pi, and then multiply it with r^3

In this case, the radius is r = 3x because this is half of the diameter d = 6x

We simply replace the r with 3x in that formula above

V = (4/3)*pi*r^3

V = (4/3)*pi*( r )^3

V = (4/3)*pi*(3x)^3 ... replace r with 3x

6 0

2 years ago

Solve for y 16y^2-25=0

Pepsi [2]

Answer:

$\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

Step-by-step explanation:

$16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}$

$METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$