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s2008m [1.1K]
3 years ago
8

B is between A and C. C is between B and D. If BC = 45 and CD is 20. If AB = CD, what is the measure of AD?

Mathematics
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

AD = 85

Step-by-step explanation:

AD = AB + BC + CD ( substitute values , noting AB = CD = 20 ) , then

AD = 20 + 45 + 20 = 85

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Which set of numbers could represent the lengths of the sides of a right triangle? 16, 32, 36 5, 12, 13 6, 7, 8 8, 12, 16
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5,12,13

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Simplify (x^2)^3*5x/6x^2*15x^3
nasty-shy [4]

When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>
  • [(x^2)^3 × 5x] / [6x^2 × 15x^3]
  • Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

  • [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

Learn more about algebra:

brainly.com/question/2768008

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2 years ago
When is estimation and affective way to determine an answer
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The temperature outside is dropping at 3°/h. Given that the temperature at noon was 0°, what would the temperature at 1 PM at 2
amm1812
Change in temp = -3/h
From noon to 1pm, 1 hour has passed, so temp = 0 degrees - 3 degrees = -3 degrees

From 1pm to 2pm, 1 hour has passed, so temp = -3 degrees - 3 degrees = -6 degrees

From 2pm to 3pm, 1 hour has passed, so temp = -6 degrees - 3 degrees = -9 degrees

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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.
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