Step-by-step explanation:
it's simple:
- 8 tens + 19ones = 9 tens + 9 ones
- 8 tens + 2 ones =7 tens+12 ones
- 7 tens +25 ones = 9 tens + 5 ones
- 70+11=80+1
- 50+13=60+3
- 90+13=100+3
9514 1404 393
Answer:
4mn/(3m+12)
Step-by-step explanation:
It is often helpful to factor expressions so that common factors can cancel.

<em>Answer:</em>
<em>x = 3</em>
<em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>0 = - 2x + 6</em>
<em>2x = 6</em>
<em>x = 6 : 2</em>
<em>x = 3</em>
<em>Good luck !</em>
Given:
The first two terms in an arithmetic progression are -2 and 5.
The last term in the progression is the only number in the progression that is greater than 200.
To find:
The sum of all the terms in the progression.
Solution:
We have,
First term : 
Common difference : 


nth term of an A.P. is

where, a is first term and d is common difference.

According to the equation,
.



Divide both sides by 7.

Add 1 on both sides.

So, least possible integer value is 30. It means, A.P. has 30 term.
Sum of n terms of an A.P. is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Substituting n=30, a=-2 and d=7, we get
![S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D%5Cdfrac%7B30%7D%7B2%7D%5B2%28-2%29%2B%2830-1%297%5D)
![S_{30}=15[-4+(29)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B%2829%297%5D)
![S_{30}=15[-4+203]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B203%5D)


Therefore, the sum of all the terms in the progression is 2985.
Answer:
Step-by-step explanation:
Divide the tens column dividend by the divisor.
Multiply the divisor by the quotient in the tens place column.
Subtract the product from the divisor.
Bring down the dividend in the ones column and repeat.
okay so look at the image down below