All categories

3 years ago

1-determine whether the function / is one-to- one:

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

3 0

Answer:

$f(t)$ is a function but not one-to-one.

Step-by-step explanation:

Please refer to my Answer from this Question to know how to Determine whether a Relation is a Function or not: brainly.com/question/24760829

This is a function because time can only move forward and there can't be different numbers of people, $f(t)$ , at the same time, $t$ . The only thing that is possible is we can have the same number of people, $f(t)$ , at the different times, $t$ . So, this isn't one-to-one but many-to-one.

You might be interested in

Helppppppppppppppppppppppp

Ratling [72]

9514 1404 393

Answer:

B, C

Step-by-step explanation:

The sums are ...

A) 59.45

B) 118.16

C) 18.97

D) 27.76

Sums B and C have 8 in the ones place.

You can add the ones-place digits. If the resulting ones-digit is 7 or 8, then add the tenths-place digits. If the carry from that sum, added to the sum of ones-place digits, gives a value of 8 or 18, then you found a sum with a ones digit of 8.

6 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

3 years ago

Read 2 more answers

-845 degree coterminal angle

meriva

Check the picture below.

with negative angles, we go "clockwise", the same direction a clock hands move.

so -360-360-125 = -845.

so as you see in the picture, you go around twice, and then a little bit more, an extra 125°, landing you at -125°, or its positive counterpart, 235°.