1-determine whether the function / is one-to- one:

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

3 0

Answer:

$f(t)$ is a function but not one-to-one.

Step-by-step explanation:

<em>Please refer to my Answer from this Question to know how to Determine whether a Relation is a Function or not: <u>brainly.com/question/2476082</u></em><em>9</em>

This is a function because time can only move forward and there can't be different numbers of people, $f(t)$ , at the same time, $t$ . The only thing that is possible is we can have the same number of people, $f(t)$ , at the different times, $t$ . So, this isn't one-to-one but many-to-one.

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Find the product of (4x − 3)(2x2 − 7x 1). 8x3 − 22x2 17x− 3 8x3 8x2 4x − 3 8x3 − 34x2 25x − 3 8x3 − 42x2 25x − 3.

Andrej [43]

Product of two polynomials can be done by distribution of multiplication over addition. The product of $(4x -3)(2x^2 -7x + 1)$ is $8x^3 - 34x^2 + 25x - 3$

<h3>What is distributive property of multiplication over addition?</h3>

Suppose a, b and c are three numbers. Then we have:

$a(b + c) = a\times b + a\times c$

(a(b+c) means a multiplied to (b+c). The sign of multiplication is usually hidden when using symbols and both quantities which are in multiplication are written together without space)

The product result of the given expression is obtained as:

$(4x -3)(2x^2 -7x + 1) = 4x(2x^2 - 7x + 1) -3(2x^2 - 7x + 1)\\(4x -3)(2x^2 -7x + 1) = 8x^{1 + 2} - 28x^2 + 4x - 6x^2 + 21x - 3\\(4x -3)(2x^2 -7x + 1) = 8x^3 + (-28-6)x^2 + (4 + 21)x - 3\\(4x -3)(2x^2 -7x + 1) = 8x^3 - 34x^2 + 25x - 3$