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3 years ago

Ive tried everything and still dont understand can you help?

Mathematics

2 answers:

vredina [299]3 years ago

7 0

Answer:

13.896 kg

Step-by-step explanation:

Volume of Gold Bar = Area of [Trapezium x Length of Bar]

Length of Bar = 16 cm

Area of Trapezium = 2 × Area of Triangle + Area of Rectangle

Area of Triangle = 0.5 × 5 × 3 = 7.5 cm²

2 × Area of Triangle = 2 × 7.5 = 15 cm²

Area of Rectangle = 6 × 5 = 30 cm²

Area of Trapezium = 15 + 30 = 45 cm²

Volume of Gold Bar = 45 × 16 = 720 cm³

Density of Gold = 19.3 g/cm³

Mass of Gold Bar = 720 × 19.3 = 13896 g = 13.896 kg

Mass of Gold Bar = 13.896 kg

Therefore the mass of the Gold Bar is: 13.896 kg (kilograms).

Rufina [12.5K]3 years ago

5 0

Answer:

13.896kg

Step-by-step explanation:

First, find the volume of the trapezium.

Volume = area of cross-sectional area times the length (16cm)

[(a+b)/2] times height

(6+12)/2 x 5

(18/2) x 5

9 x 5

= 45 <-- area of cross section

45 x 16 = 720 cm^3 <-- volume

To find the mass, multiply volume times density

720 x 19.3 = 13 896g = 13.896kg

For detailed, step-by-step explanations you can visit my fiverr account: kesja_

I provide detailed explanations for math questions for as little as $1!

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arlik [135]

Answer:

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Step-by-step explanation:

The Weight of Ingredients to be used by Chef Selena are:

$5\frac{1}{8}$ pounds of pasta,
6 pounds of sauce; and
$4\frac{7}{8}$ pounds of onions.

Total Weight of Food Made, x

$=5\frac{1}{8}+6+4\frac{7}{8}\\=5+6+4+\frac{1}{8}+\frac{7}{8}\\=16 \: Pounds$

Since each serving is $\frac{1}{2} Pounds$

Number of Servings of her dish, y

$16 \div \frac{1}{2}\\ =32 \: Servings$

The two equations needed to solve the problem are therefore:

$\text{Total Weight of Food Made}, x=5\frac{1}{8}+6+4\frac{7}{8}\\\text{Number of Servings}, y=x \div \frac{1}{2}$

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3 years ago

Please help asap, will give brainiest. TY! :3

lilavasa [31]

Answer:

Page 1::1 & 3 & 4

Page 2:6

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Step-by-step explanation:

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3 years ago

3. Segment MN has endpoints at M(-6, -3) and N(9,7). Point Q lies on MN such that MQ:QN = 3:2.

Aleks04 [339]

Given:

Segment MN has endpoints at M(-6, -3) and N(9,7).

Point Q lies on MN such that MQ:QN = 3:2.

To find:

The coordinates of point Q.

Solution:

Section formula: If a point divides of line segment whose end points are $(x_1,y_1)$ and $(x_2,y_2)$ in m:n, then the coordinates of that points are:

$Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Segment MN has endpoints at M(-6, -3) and N(9,7) and Point Q lies on MN such that MQ:QN = 3:2. By using section formula, we get

$Q=\left(\dfrac{3(9)+2(-6)}{3+2},\dfrac{3(7)+2(-3)}{3+2}\right)$

$Q=\left(\dfrac{27-12}{5},\dfrac{21-6}{5}\right)$

$Q=\left(\dfrac{15}{5},\dfrac{15}{5}\right)$

$Q=\left(3,3\right)$

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3 years ago

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Nikolay [14]

Answer:

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Step-by-step explanation:

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Needed time = 11:10

This means that they ought to start their tour by 11:10 am, so that they can meet their dinner

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evablogger [386]

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