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2 years ago

Ive tried everything and still dont understand can you help?

Mathematics

2 answers:

vredina [299]2 years ago

7 0

Answer:

13.896 kg

Step-by-step explanation:

Volume of Gold Bar = Area of [Trapezium x Length of Bar]

Length of Bar = 16 cm

Area of Trapezium = 2 × Area of Triangle + Area of Rectangle

Area of Triangle = 0.5 × 5 × 3 = 7.5 cm²

2 × Area of Triangle = 2 × 7.5 = 15 cm²

Area of Rectangle = 6 × 5 = 30 cm²

Area of Trapezium = 15 + 30 = 45 cm²

Volume of Gold Bar = 45 × 16 = 720 cm³

Density of Gold = 19.3 g/cm³

Mass of Gold Bar = 720 × 19.3 = 13896 g = 13.896 kg

Mass of Gold Bar = 13.896 kg

Therefore the mass of the Gold Bar is: 13.896 kg (kilograms).

Rufina [12.5K]2 years ago

5 0

Answer:

13.896kg

Step-by-step explanation:

First, find the volume of the trapezium.

Volume = area of cross-sectional area times the length (16cm)

[(a+b)/2] times height

(6+12)/2 x 5

(18/2) x 5

9 x 5

= 45 <-- area of cross section

45 x 16 = 720 cm^3 <-- volume

To find the mass, multiply volume times density

720 x 19.3 = 13 896g = 13.896kg

For detailed, step-by-step explanations you can visit my fiverr account: kesja_

I provide detailed explanations for math questions for as little as $1!

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Step-by-step explanation:

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y=4*0-7

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2 years ago

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2 years ago

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Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

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Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

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Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

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$\frac{2(-3x + 2)}{6(3x - 1)}$

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2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

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$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

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3 years ago

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sesenic [268]

Answer:

x = 3

Step-by-step explanation:

5x - 8 + 8 = 7 + 8

5x = 15

5x/5 = 15/5

15 divided by 5 equals 3

Hope this helped you out :)

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2 years ago

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aliya0001 [1]

Answer:

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$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

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and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

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2 years ago