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Alborosie
3 years ago
10

The length of a rectangle is four times its width.

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0
Let L represent length of rectangle

Let W represent width of rectangle

L=4W

2L+2W=70

Substitute 4W for L

2(4W)+2W=70

8W+2W=70

10W=70

Divide both sides by 10

W=7

Use equation from beginning

L=4(7)

L=28

Width is 7 ft, length is 28 ft

Check work

2(28)+2(7)=70

56+14=70

70=70
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Marcel made an error when he used the distributive property to solve the problem shown. Which sentence describes the error?
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The answer to this is step 2 because they multiplied when they should of subtracted the 10 and the 12.
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Sheng ran 2 2/3 miles and walked 1 mile. How much farther did Sheng run than walk
nadezda [96]

Answer: 1 2/3 more

Step-by-step explanation:

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3 years ago
Write an equation for the following table.
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Lets pick to columns in the table

Lets so (6,228) and (7,266)

To find the slope you need to do y1-y2/x1-x2

7-6/266-228=1/38.

1/38 is the slope.

y=1/38x+b

to find B you have to plug any of the y with the corresponding x values back in and solve for b.

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228=1/38(6)+b

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6 0
3 years ago
A research team conducted a study showing that approximately 25% of all businessmen who wear ties wear them so tightly that they
Sonbull [250]

Answer:A) 0.9866

Step-by-step explanation:

Probability of at least one tie is too tight is

Probability of tight tie 25/100

Probability of not a tight tie is 1-25/100=3/4

=1-(3/4)^15=0.9866

B)0.764

C)0.013

D)0.236

Method 2

This is binomial probability.

n=15 (number of businessmen

p=.25 (probability that a businessman wears the tie so tightly

A)

x = number of businessmen out of 15 who wears the tie so tightly

P( at least 1) = P( x >= 1) = 1-P(x=0)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P( at least 1) = 1- 0.013363 = 0.9866

B)

P(more than 2) = P( x > 2) = 1-P( x=0)-P(x=1)-P(x=2)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P(x=1) = 15C1 (.25)^1 (.75)^14 = 0.066817

P(x=2) = 15C2 (.25)^2 (.75)^13 = 0.155907

1-P( x=0)-P(x=1)-P(x=2) = 1 - 0.013363 - 0.066817 - 0.155907 = 0.763912

C)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

D)

P( at least 13) = P(x=13)+P(x=14)+P(x=15)

P(x=13)= 15C13 (.25)^13 (.75)^2 = 0.000001

P(x=14)= 15C14 (.25)^14 (.75)^1 = 0.000000

P(x=15)= 15C15 (.25)^15 (.75)^0 = 0.000000

P(x=13)+P(x=14)+P(x=15) = .000001+.000000+.000000 = 0.000001

4 0
4 years ago
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I need help with number 1
rjkz [21]

Answer:∠1=55° ∠2=55° ∠3=55° ∠4=70° ∠5=55°

Step-by-step explanation:

We know that opposite angles of rhombus are congruent and the diagonals of rhombus cut the vertex angles into half. So ∠4=70° and ∠2=∠3=∠1=∠5.

Let ∠2+∠3=x

the sum of four angles of rhombus= 360°

70+70+ x +x = 360°

140+2x = 360°

2x=220°

x=110°

∠2=110°/2=55°=∠3=∠1=∠5

3 0
3 years ago
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