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Nana76 [90]
3 years ago
15

Label some of the main service provided by the internet.using the picture​.. please...

Computers and Technology
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

Social media

Laptops

Phones

Emails

Please give brainliest

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How can you troubleshoot Internet access problems?
joja [24]

Answer:

Check the network icon (or wireless connection settings) to see if you have Internet access. ...

Check for changes to proxy settings.

Check the network cables if your computer is wired to the router.

Reset your router.

Check your firewall or security software.

Hopefully this helps.

8 0
3 years ago
Router 1 is configured with static NAT. Addressing on the router and the web server are correctly configured, but there is no co
marin [14]

Answer:

The router NAT configuration has an incorrect inside local address.

Explanation:

The term Inside in a <em>Network Address Translation (NAT) </em>context refers to networks owned by an organisation that must be translated. When NAT is configured, hosts within this network have addresses in one space (known as the local address space). These hosts appear to those users outside the network as being in another space (known as the global address space).

The term Outside refers to those networks to which the stub network connects, and which are not under the control of an organisation. Also, hosts in outside networks can be subject to translation, and can thus have local and global addresses

7 0
3 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
Which structures protect the cell? Select two options.
Rzqust [24]

Answer:

cell wall

cell membrane

3 0
2 years ago
What keyword can we use within a form to pass it as an argument to a JavaScript snippet? A. form B. onSubmit C. send D. this
astraxan [27]

C. send is your answer

3 0
3 years ago
Read 2 more answers
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