Answer:
85, 68, 51
Step-by-step explanation:
Average: The sum of all the numbers divided by the number of numbers
If the ratio of the scores is 5 : 4 : 3, let's just set it as 5x : 4x : 3x
Then using the definition of an average, we can write this equation.
(5x + 4x + 3x) / 3 = 68
Multiply both sides by 3.
5x + 4x + 3x = 68 * 3
Simplify.
12x = 204
x = 17
Now, substitute x = 17 into the original scores (5x, 4x, and 3x)
5x = 5 * 17 = 85
4x = 4 * 17 = 68
3x = 3 * 17 = 51
Just in case, let's check this answer. Find the average of the 3 test scores.
(85 + 68 + 51) / 3 =
204 / 3 = 68
Thus, the answers are correct
Answer:
d. 76.98%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What percentage of MBA's will have starting salaries of $34,000 to $46,000?
This is the pvalue of Z when X = 46000 subtracted by the pvalue of Z when X = 34000. So
X = 46000



has a pvalue of 0.8849
X = 34000



has a pvalue of 0.1151
0.8849 - 0.1151 = 0.7698
So the correct answer is:
d. 76.98%
Answer:
2:50 PM
Step-by-step explanation:
Step 1: State what is given
Roast takes 3 hours and 40 minutes or 220 minutes
Need the roast to be done by 6:30 PM
Step 2: Subtract 3 hours from 6:30
6:30 - 3:00
3:30 PM
Step 3: Subtract 40 minutes from 3:30
3:30 - 40
2:50 PM
Therefore the roast needs to be put into the oven at 2:50 PM
Just addum up.
You should get the sum of 1.981 .
That's in standard form.
Answer:
20
Step-by-step explanation:
To get the answer, you have to find what number 15 is 75 percent of.