1. Each shelf holds 5 hermit-crab cages. There are 23 hermit crab cages to be displayed. Divide the number of hermit crab cages to be displayed by the number of hermit crab cages that can be displayed on each shelf:
This means that you need 5 shelves (4 shelves is not enough, because 3 hermit crab cages will be not displayed).
2. Each shelf holds 3 hermit-crab care booklets. There are 12 hermit-crab care booklets to be displayed. Divide the number of hermit-crab care booklets to be displayed by the number of hermit-crab care booklets that can be displayed on each shelf:
This means that you need 4 shelves.
Answer: first, you have to divide 23 by 5 and find the quotient and remainder and divide 12 by 3 and find the quotient and remainder. Then you have to determine the number of shelves needed. You need 5 shelves.
Answer:
A: they are equal in length to the sides of the base
Step-by-step explanation:
The distance between both lines is 2.24 units
Step-by-step explanation:
There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.
Given
We have to find the distance of this point from y=2x+5
The formula for finding distance of a point (x,y) from a line is:
A=2
B=-1
C=5
Putting the values in the formula
Rounding off will give: 2.24 units
The distance between both lines is 2.24 units
Keywords: Equations of lines
Learn more about distance in lines at:
#LearnwithBrainly
Answer:
202 cm^2
Step-by-step explanation:
SA = 2LW + 2LH + 2WH
SA = 2(4 cm)(5 cm) + 2(4 cm)(9 cm) + 2(5 cm)(9 cm)
SA = 40 cm^2 + 72 cm^2 + 90 cm^2
SA = 202 cm^2
Answer:
(a) 120 choices
(b) 110 choices
Step-by-step explanation:
The number of ways in which we can select k element from a group n elements is given by:
So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:
Then each student have 120 possible choices.
On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:
1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:
2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:
3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:
So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:
50 + 50 + 10 = 110
