First write both vectors in terms of their horizontal and vertical components.
G = (40.3 m)(cos(-35.0º) x + sin(-35.0º) y)
G = (33.0 x - 23.1 y) m
(where x and y are the unit vectors that point in the positive horizontal and vertical directions, respectively)
H = (63.3 m)(cos 270º x + sin 270º y)
H = (-63.3 y) m
Then the vector sum is
G + H = (33.0 x - 86.4 y) m
which has a magnitude of
|| G + H || = √[33.0^2 + (-86.4)^2] = 92.5 m
Answer:
B . Yes
Step-by-step explanation:
Recall: a tangent of a circle is perpendicular to the radius of a circle, forming a right angle at the point of tangency.
Therefore, if segment ST is tangent to circle P, it means that m<T = 90°, and ∆PST is a right triangle.
To know if ∆PST is a right triangle, the side lengths should satisfy the Pythagorean triple rule, which is:
c² = a² + b², where,
c = longest side (hypotenuse) = 37
a = 12
b = 35
Plug in the value
37² = 12² + 35²
1,369 = 1,369 (true)
Therefore we can conclude that ∆PST is a right triangle, this implies that m<T = 90°.
Thus, segment ST is a tangent to circle P.
Step-by-step explanation:
-3(-x -3y) = 3( x +3y) = 3x+9y
Answer:
The most reasonable answer would likely be the first.
"When a pair of parallel lines is intersected by a third line, the alternate exterior angles are congruent."
Step-by-step explanation:
