Answer:the quotient of 16 and x=4
Step-by-step explanation:
Answer:
1. (-7, 5 ) and (-1, 3)
(3-5)/(-1+7)= -2/6 = -1/3
y - 5 = (-1/3)(x + 7)
y - 5 = (-1/3)x - 7/3
y - 15/3= (-1/3)x - 7/3
y = (-1/3)x + 8/3
2. (-1-3)/(3-0)= -4/3
y + 3 = (-4/3)(x + 1)
y + 3 = (-4/3)x - 4/3
y + 9/3 = (-4/3)x - 4/3
y = (-4/3)x + 5/3
the answer is neither
Answer:
8y^3+6y^2-29y+15
Step-by-step explanation:
the correct expression is
(4y − 3)(2y^2 + 3y − 5)
Given data
We have the expression
(4y − 3)(2y^2 + 3y − 5)
let us open bracket
8y^3+12y^2-20y-6y^2-9y+15
Collect like terms
8y^3+12y^2-6y^2-20y-9y+15
8y^3+6y^2-29y+15
I've included two pictures showing steps on how to solve. Hopefully this helps more than words.