Anyone know how to do this ! ?

Find V when l = 6ft, w= 3ft, and h= 9ft.

dolphi86 [110]

Answer:

162

Step-by-step explanation:

V = L X W X H

V = 6 X 3 X 9

6 times 3 is 18

V = 18 X *

18 times 9 is 162

V = 162

hope this helped :D

6 0

3 years ago

write an equation to solve for x your only writing the equation. 7x+9 5×+3 there's three answers the bottom one is if none of th

professor190 [17]

Answer:

Step-by-step explanation:

its a supplementary angles:

so the equation is add the two equation equals to 180

7x + 9 + 5x + 3 = 180

3 0

3 years ago

A square base of a pyramid has dimensions 5 yards by 5 yards. The height of one of the triangular faces is 12 yards. How can you

siniylev [52]

A square pyramid has 4 triangles and the square base.

Calculate the area of one triangle, multiply that by 4 then add the area of the base.

Area of triangle = 1/2 x base x height = 1/2 x 5 x 12 = 30 square yards.

30 x 4 = 120 square yards

Area of base = 5 x 5 = 25 square yards

Total = 120 + 25 = 145 square yards.

7 0

3 years ago

the length of a rectangle is 6 meters less than twice the width. The area of the rectangle is 140m². Find the dimensions of the

AveGali [126]

Answer:

Here's what we know:

A = Lw (Area is length times width)

L = 2w + 6 (length is twice the width plus 6)

A = 140 (Area is 140 m2)

Plug in the variable values:

140 = w(2w + 6)

Distribute:

140 = 2w2 + 6w

Subtract 140:

2w2 + 6w - 140 = 0

Factor out a 2:

2(w2 + 3w - 70) = 0

Divide both sides by 2:

w2 + 3w - 70 = 0

(w + m)(w - n)

When we factor out the quadratic, we know it's going to be a +/- situation because the c value in the quadratic is negative, and the two numbers are going to be three away, the plus next to the 3 meaning that the larger number is going to be positive:

(w + 10)(w - 7) = 0

w = -10, 7

We can't have a negative length, so we can toss out the -10, leaving us with w = 7 meters.

L = 2 * 7 + 6

L = 14 + 6

L = 20

Check:

140 = 20 * 7

140 = 140

8 0

3 years ago

Read 2 more answers

Charlie guesses that his dog weighs 34. 5 pounds. The dog actually weighs 32. 7 pounds. What is the percent error in Charlie’s g

expeople1 [14]

Percent error is the amount of error to actual value, in percent. The percent error in Charlie’s guess is approximately: Option D: 5.5%

<h3>How to calculate the percent error?</h3>

Suppose the actual value and the estimated values after the measurement are obtained. Then we have:

Error = Actual value - Estimated value

To calculate percent error, we will measure how much percent of actual value, the error is, in the estimated value.

$\rm Percent \: Error = |\dfrac{Error}{Actual value}|\times 100 \\\\Percent \: Error = | \dfrac{\text{(Actual Value - Estimated Value)}}{Actual value}|\times 100 \\$

(here |x| is such that it makes x non negative, thus, |-5| = 5, and |5| = 5)

For the given case, it is specified that:

Actual weight of dog = 32.7 pounds

Guessed weight of dog, by Charlie : 34.5 pounds.

Error = 32.7 - 34.5 = -1.8 pounds

Thus, percent error in Charlie's guess is calculated as:

$\text{Percent Error} = |\dfrac{-1.8}{32.7}| \times 100 \approx 5.5\%$

Hence, the percent error in Charlie’s guess is obtained approximately is given by: Option D: 5.5%

Learn more about percent error here:

brainly.com/question/25749180

3 0

2 years ago