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lisov135 [29]
2 years ago
12

Is it correct way? answer in the picture​

Mathematics
2 answers:
grin007 [14]2 years ago
6 0
The correct answer is 56 :)
sattari [20]2 years ago
4 0

Answer:56

Step-by-step explanation:

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Sean borrowed some money from his friend in order to help buy a new video game system. Sean agreed to pay back his friend $10 pe
aliya0001 [1]

Answer: (10)9

Step-by-step explanation:

6 0
3 years ago
Sam says 90 ÷ (–9) = 10. Is he correct? Use the drop–down menus to explain your answer.
SashulF [63]

Answer:

No.

Step-by-step explanation:

Sam is incorrect because if you look at the original problem, you'll see that he has missed the negative sign!

90 / 9 does equal 10, but 90 / -9 equals -10.

The only way to get a positive answer is if both the divisor and dividend are positive or if they are both negative.

Thus, the correct answer should be -10.

3 0
3 years ago
Evaluate 0.1m + 8 - 12n when = 30 and n = 1/4<br><br> ​
Nastasia [14]

Answer:m=250

Step-by-step explanation:

0.1m+8-3=30

0.1m+5=30

0.1m=25

0.1 times 250=25

m=250

6 0
3 years ago
Read 2 more answers
63. 26 Which expressions are equal to 23 ? 123 126 26 . 33 23 33​
liubo4ka [24]

Hey there!

(6^3 * 2^6) / 2^3

= (6 * 6 * 6 * 2 * 2 * 2 * 2 * 2 * 2) / 2 * 2 * 2

= (36 * 6 * 4 * 4 * 4) / 4 * 2

= (216 * 16 * 4) / 8
= 3,456 * 4 / 8

= 13,824 / 8

= 1,728


Looking for something that gives you the result of: 1,728


Option A.
12^3

= 12 * 12 * 12

= 144 * 12

= 1,728

Option A. is. possible answer


Option B.
6^3

= 6 * 6 * 6

= 36 * 6

= 216

216 ≠ 1,728

Option B. is incorrect


Option C.
12^6

= 12 * 12 * 12 * 12 * 12 * 12

= 144 * 144 * 144

= 20,736 * 144

= 2,985,984

2,985,984 ≠ 1,728

Option C. is also incorrect


Option D.
2^6 * 2^3

= 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2

= 4 * 4 * 4 * 4 * 2

= 16 * 16 * 2

= 256 * 2

= 512
512 ≠ 1,728

Option D. is also incorrect

Option E.
2^3 * 3^3

= 2 * 2 * 2 * 3 * 3 * 3

= 4 * 2 * 9 * 3

= 8 * 27

= 216

216 ≠ 1,728

Option E. is also incorrect.


Therefore, the answer should be:

Option A. 12^3



Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

3 0
2 years ago
Roster method of A = {x | x is an odd number and 20 &lt; x &lt; 30}
Sunny_sXe [5.5K]

A "roster" here is essentially a version of the set with all of elements listed out. Here, those elements are all of the odd numbers between 20 and 30, so our list would be

{21, 23, 25, 27, 29}

3 0
3 years ago
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