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Anarel [89]
3 years ago
10

PLS HELP ME GRADUATE ILL MARK BRAINLY A-AND ILL GIVE U A COOKIE!!! PLS

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

Dilate circle A by a scale factor of 4.

Step-by-step explanation:

Dilating circle A by 4 would be the same as multiplying its radius of 6 by 4, which would make it 24.

The radius of circle B is 24.

Rotating it wouldn't change anything (it's a circle), and I don't think reflecting and translating show circle similarity

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Simplify (3x + 5) + (2x - 9) - (4x+3).<br><br><br> A.) X-7<br> B.) -X-7<br> C.) 9x1<br> D) 9x1
erica [24]

Answer:

x -7

Step-by-step explanation:

(3x + 5) + (2x - 9) - (4x+3)

3x + 5 + 2x - 9 -4x -3

x -7

8 0
2 years ago
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10 POOIINNTTS and Branliest!!! <br><br> What is Exponential Form?​
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Answer:

It mean's numeric form with exponents.

Step-by-step explanation:

Basically it's a way to write the number better without having to repeat it.

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3 years ago
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Write a quadratic function in standard form with a leading coefficient of 1 for the given set of zeros. 7 and 4
Viefleur [7K]

We are given : Zeros x=7 and x=4 and leading coefficent 1.

In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.


6 0
3 years ago
A ratio equivalent to 2:5 is 2 :10
azamat
False... a ratio equivalent to 2:5 is 4:10

2/5 × 2/2 = 4/10
8 0
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An object placed between two plane mirrors arranged at right angles to each other at a distance d1 from the surface of one mirro
xz_007 [3.2K]

Answer:

3

..................

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