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3241004551 [841]
3 years ago
9

YA'LL ARE SMART!!! PLEASE HELP!!!

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

first answer!

Step-by-step explanation:

domain: all real numbers

range: all real numbers greater than or equal to 5!

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Tell whether the angles are adjacent or vertical. Then find the value of x. x =?
baherus [9]

Answer:

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Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
OleMash [197]

ANSWER



x=1.39 to the nearest hundredth.



EXPLANATION



We have the equation,



0=2x^2+3x-8



Which can be rewritten as



2x^2+3x-8=0

The question demands the use of the quadratic formula.

Comparing this to the general quadratic equation;

ax^2+bx+c=0


a=2,b=3,c=-8


The quadratic formula is given by;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}


We now substitute all the values in to the formula;


x=\frac{-3\pm\sqrt{(3)^2-4(2)(-8)}}{2(2)}

We simplify to obtain;

x=\frac{-3\pm\sqrt{9+64}}{4}


x=\frac{-3\pm\sqrt{73}}{4}


We now split the plus or minus sign to obtain;


x=\frac{-3-\sqrt{73}}{4}


This implies that;


x=-2.89

Or

x=\frac{-3+\sqrt{73}}{4}


This will evaluate to;


x=1.39

Hence, the positive solution rounded to the nearest hundredth is

x \approx 1.39

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