Answer:
See answer and graph below
Step-by-step explanation:
∬Ry2x2+y2dA
=∫Ry.2x.2+y.2dA
=A(2y+4Ryx)+c
=∫Ry.2x.2+y.2dA
Integral of a constant ∫pdx=px
=(2x+2.2Ryx)A
=A(2y+4Ryx)
=A(2y+4Ryx)+c
The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2
1200, (2)3+(2)2+2 = 6+4+2 = 12 12(100)= 1200
Answer:
94
Step-by-step explanation:
im pretty sure this is right
Answer:
25
I hope i got it in time :)
hi sorry I can't help with that