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3 years ago

Which steps could be part of the process in algebraically solving the system of equations, y + 5x = x2 + 10 and y = 4x –

Mathematics

1 answer:

mafiozo [28]3 years ago

3 0

Answer:

0 = x2 - 9x + 20

Step-by-step explanation:

y + 5x = x² + 10 Simplify this equation

- 5x - 5x

y = x² - 5x + 10

Set both equations equal to each other since they both equal y

x² - 5x + 10 = 4x - 10

-4x - 4x

x² - 9x + 10 = -10

+ 10 + 10

x² - 9x + 20 = 0

If this answer is correct, please make me Brainliest!

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Solve the equation. 9x−(3x+9)=2x−25 Select the correct choice below and fill in any answer boxes in your choice. A. The solution

nataly862011 [7]

Answer: Choice A, x=-4

Step-by-step explanation:

1. 9x−(3x+9)=2x−25

2. 9x-3x-9=2x-25

3. 6x-9=2x-25

4. 6x-9=2x-25

-2x -2x

5. 4x-9=-25

+9 +9

6. 4x=-16 (divide both sides by 4)

7. x=-4

7 0

3 years ago

If you are traveling 543 miles and you know that your car gets 18 miles per gallon of gasoline, approximately how many gallons o

Inga [223]

we know that

the car gets 18 miles per -----------> 1 gallon of gasoline

for 543 miles ---------------------> x gallons of gasoline

by proportion

543/18=x/1---------->x=543/18------->x=30.17 gallons

therefore

the answer is

30.17 gallons

6 0

3 years ago

Can some solve me this one question

iogann1982 [59]

What is the question?

7 0

3 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago

jen makes a rectangular banner. it is 3/4 yard long and 1/4 yard wide. what is the area, in square yards of the banner

SashulF [63]

Ok so in order to find the answer to this problem we are going to Multiply $\frac{3}{4}$ and $\frac{1}{4}$ . $\frac{3}{4}* \frac{1}{4}= \frac{3}{4}
$ $Answer:\boxed{ \frac{3}{4}} \\ 
$

8 0

3 years ago

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