Answer:
Ravi’s average speed is 7 miles per hour
Step-by-step explanation:
In this question, we are tasked with calculating what Ravi’s average speed was.
We must know that the term average speed is mathematically equal to Total distance/ Total time
We already have the time of 3 hours, what is needed is the distance.
From the question, we can see that they met at the point where Pilar had travelled 55 miles. What this means is that Ravi would have traveled (55-34) miles to this point since they are coming in opposite direction. This means that Ravi had traveled 21 miles
Thus his average speed is 21 miles/ 3 hours = 7 miles per hour
Answer:
Slope- 5 y-int- (0,0)
Step-by-step explanation:
y=mx+b, where m=slope and b=y-int. m=5, and we don't see a b, so it must be 0.
Answer
Length = 10 ft
Width = 5 ft
Explanation
Area of the rectangle given = 50 ft²
Let the width of the rectangle be x
So this means the length of the rectangle will be 3x - 5
What to find:
The dimensions of the rectangle.
Step-by-step solution:
Area of a rectangle = length x width
i.e A = L x W
Put A = 50, L = 3x - 5, W = x into the formula.

The quadratic equation can now be solve using factorization method:

Since the dimension can not be negative, hence the value of x will be = 5.
Therefore, the dimensions of the rectangle will be:
Answer: 
Step-by-step explanation:
Some transformations for a function f(x) are shown below:
If
, the function is translated up "k" units.
If
, the function is translated down "k" units.
If
, the function is reflected across the x-axis.
If
, the function is reflected across the y-axis.
Therefore, knowing those transformations and given the exponential parent function:

If it is reflected across the y-axis and the it is translated down 4 units, we can determine that the resulting function is:

So we are looking for the GCF which is the largest factor that the two numbers have in common, so you would want to circle all of the number that the two have in common. So it would be 2 twos and 2 X's (2,2,x,x). Which is the most numbers that the two have in common.