The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>
The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
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Answer 5x 1y 5 1
Step-by-step explanation:
Is this a simultaneous equation question?
Answer:
z=-4
Step-by-step explanation:
Simplify 10 + 2z + 2z to 10 + 4z
Add 10 to both sides
Simplify 10 + 4z + 10 to 4z + 20
Subtract 4z from both sides
Simplify -z - 4z − z− 4z to -5z − 5z.
Divide both sides by -5 − 5
Simplify 20 / 5 to 4