The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
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Answer:
B.) 36/60
Step-by-step explanation:
some
equivalent fractions of 9/15:
3/5 = 6/10 = 9/15 = 12/20 = 15/25 = 18/30 = 21/35 = 24/40 = 27/45 = 30/50 = 33/55 = 36/60
The horizontal distance between light house and boat is 1588.78 feet approximately.
The figure is given by,
Here, AB = height of the lighthouse bacon light above the water = 139 feet
Now angle ACB = 5 degree
Let the horizontal distance of light house from the boat = BC = x feet
So by trigonometric function we get,
tan 5 = AB/BC
tan 5 = 139/x
x = 139/tan 5 = 1588.78 (approximately)
Hence the horizontal distance between light house and boat is 1588.78 feet approximately.
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