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NemiM [27]
3 years ago
10

Drag each value to the correct location on the table. Identify whether the given numbers are perfect squares, perfect cubes, or

neither. 8, 9, 21, 27, 1331, 1332, 100, 1,000, 126, 125, 25, 81.
Mathematics
2 answers:
Maru [420]3 years ago
7 0

9- square

100- square

25- square

81- square

8- cube

27- cube

1331- cube

1000- cube

21- neither

1332- neither

126- neither


eduard3 years ago
6 0

Answer:

Cubes 8, 27, 1331, 1000, 125 Squares 9, 100, 25, 81 and neither are 21, 1332, 126.

Step-by-step explanation:

The given numbers are 8, 9, 21, 27, 1331, 1332, 100, 1000, 126, 125, 25, 81 and we have to find the perfect squares, perfect cubes or neither from these numbers.

8=2^{3}

9=3^{2}

21 is neither square nor cube.

27 = 3³

1332 is niether

1331 = 11³

100 = 10²

1000 = 10³

126 neither

125 = 5³

25 = 5²

81 = 9²

So cubes are 8, 27, 1331, 1000, 125 and squares are 9, 100, 25, 81.

Neither are 21, 1332, 126.

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So P(Y|X) = P(Y)

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Read 2 more answers
The top and bottom margins of a poster are 8 cm and the side margins are each 6 cm. If the area of printed material on the poste
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Answer:

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Width  29.10 cm

Height 38.80 cm

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Step-by-step explanation:

Printed area = 390 cm² = Ap

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x   width

y   height

Then Ap = x*y    and

y = Ap/x    ⇒    y = 390/x

Then   total area of the poster is:

A(t)  = ( x  + 12 ) * ( y + 16 )         and   y = 390/x

A as a function of x

A(x) = ( x  + 12 ) * ( 390/x + 16 )   ⇒  A(x) = 390 + 16x + 4680/x + 192

A(x) = 582 + 16x + 4680/x     (1)

Taking derivatives

A´(x) =  16 - (4680/x²)         ⇒ A´(x)  =  0

[ 16x² -4680] /x² = 0     16x²- 4680 = 0    ⇒     x² = 4680/16

x = 17.10 cm        and    y = 390/x      y = 390/17.10      y = 22.80 cm

A(t) = ( 17.10 + 12 ) * ( 22.80 + 16 )

A(t) = 29.10 * 38.80

A(t) = 1129.08 cm²

If we substitute  in equation (1) the value of x  ( 17.10) we see A(x) > 0

Then there is a minimun at the point x = 17.10

4 0
3 years ago
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